如何访问类中子函数的变量？

Question

我在调用一个子函数外的变量时遇到了问题。

class ABC():
    def ___init___(self):
        function_A()
        function_B()
    def function_A(self):
        self.A = 5
        def subfunction_of_A(self):
            self.B = 2
            self.function_B()
        subfunction_of_A()
    def function_B(self):
        C = self.B

 Start = ABC()

我总是出现错误。'ABC' object has no attribute 'B' for C = self.B

如何让self.B从外部访问？

非常感谢:)

class ABC():
    def ___init___(self):
        self.function_A()
        self.function_B()
    def function_A(self):
        self.A = 5
        def subfunction_of_A(self):
            self.B = 2
        subfunction_of_A(self)
        print(self.B) # This prints 2 and works as it should!
    def function_B(self):
        C = self.B # In this line I receive the error that ABC.B does not exist --> Why is that?

 Start = ABC()

Answer 1

编辑。

class ABC():
    def __init__(self):
        self.function_A()
        self.function_B()
    def function_A(self):
        self.A = 5
        def subfunction_of_A(self):
            self.B = 2
        subfunction_of_A(self)
    def function_B(self):
        print(self.B) # This prints 2 and works as it should!
        C = self.B

Start = ABC()

这次你的问题似乎是你的 ___init___ 有3个下划线而不是2个... __init__

上一个答案。

你从未调用过你的 "子函数"

class ABC():
    def function_A(self):
        self.A = 5
        def subfunction_of_A(self):
            self.B = 2
        subfunction_of_A(self) # notice this line

    def function_B(self):
        self.C = self.B


abc = ABC()
abc.function_A()
abc.function_B()
print(abc.C) # prints 2

设置B的唯一方法是让函数运行，即使它是嵌套的......这是一种奇怪的设置类的方法，但你会发现