我正在使用codeIgniter文件上传类示例https://www.codeigniter.com/user_guide/libraries/file_uploading.html来上传文件。在上传文件后的示例中,它将在上传成功视图页面中显示如下所示的详细信息。
Array
(
[upload_data] => Array
(
[file_name] => VenkataKrishna10.pdf
[file_type] => application/pdf
[file_path] => C:/xampp/htdocs/upload/application/
[full_path] => C:/xampp/htdocs/upload/application/VenkataKrishna10.pdf
[raw_name] => VenkataKrishna10
[orig_name] => VenkataKrishna.pdf
[client_name] => VenkataKrishna.pdf
[file_ext] => .pdf
[file_size] => 83.27
[is_image] =>
[image_width] =>
[image_height] =>
[image_type] =>
[image_size_str] =>
)
)
之后我尝试以数组格式查看整个上传的数据。我的问题是如何从上面的数组获取完整的文件路径。我知道有一个变量full_path
但我无法得到它。请帮我。
从您的控制器使用
echo $data['upload_data']['full_path'];
从您的角度来看
echo $upload_data['full_path'];
试试这样:
if ( ! $this->upload->do_upload())
{
$error = array('error' => $this->upload->display_errors());
}
else
{
$data = $this->upload->data();
// $data will contain full inforation
echo "Full path is:". $data['full_path'];
}
从你发布,我假设你已经从某个变量的print_r给出了输出,比如$file_detail
。
如果你想从$file_detail
获得full_path,你必须使用
$file_detail['upload_data']['full_path']
成功上传后返回数组,您只需要检索索引键:
控制器:
if ( ! $this->upload->do_upload())
{
$data['error'] = $this->upload->display_errors();
}
else
{
$data['upload_data'] = $this->upload_data();
}
$this->load->view('myview', $data);
myview.php
<p>Full path: <?php echo $upload_data['full_path'];?></p>
如果要在插入数据库后从上传中删除文件,可以使用unlink($ filename)从上传文件中删除文件