Javascript：在新数组中映射两个数组的值

Question

我有两个对象数组，如下所示：

const data = [
  {
    id: 1,
    condition: 1,
    helpers: [{id: 1, condition: null}, {id: 2, condition: 2}]
  },
  {
    id: 2,
    condition: null,
    helpers: [{id: 1, condition: 1}, {id: 2, condition: null}]
  }
]

const conds = [
  {
    id: 1,
    conditions: {
       rules: ['test', 'foo']
    }
  },
  {
    id: 2,
    conditions: {
       rules: ['#hashtag', 'foo']
    }
  }
]

我试图实现的是，我想用condition数组中的data数组替换conds数组的

let newArray = [];

data.forEach(obj => {
        conds.forEach(cond => {
            if (obj.condition) {
                if (obj.condition === cond.id) {
                    obj.condition = cond.conditions.rules;
                    newArray.push(obj);
                }
            } else {
                obj.helpers.forEach(h => {
                    if (h.condition && h.condition === cond.id) {
                        h.condition = cond.conditions.rules;
                        newArray.push(obj);
                    }
                });
            }
        })
    });

值。

我的解决方案效果不好看起来像这样：

newArray

我觉得我非常接近解决方案，因为我的condition包含更改属性，但不包含帮助程序内的最后一项，而

[
  {
     id: 1
     condition: ['test', 'foo'],
     helpers: [{id: 1, condition: null}, {id: 2, condition: ['#hashtag', 'foo']}]
  },
  {
     id: 2
     condition: null,
     helpers: [{id: 1, condition: ['test', 'foo']}, {id: 2, condition: null}]
  },
]

属性仍然是2。

输出应如下所示：

const data = [
  {
    id: 1,
    condition: 1,
    helpers: [{id: 1, condition: null}, {id: 2, condition: 2}]
  },
  {
    id: 2,
    condition: null,
    helpers: [{id: 1, condition: 1}, {id: 2, condition: null}]
  }
]

const conds = [
  {
    id: 1,
    conditions: {
       rules: ['test', 'foo']
    }
  },
  {
    id: 2,
    conditions: {
       rules: ['#hashtag', 'foo']
    }
  }
]

// START SOLUTION

const rulesMap = conds.reduce((map, condition) => {
    map[condition.id] = condition.conditions.rules;
    return map;
}, {});

const finalData = data.map(dataItem => {
    dataItem.condition = dataItem.condition ? rulesMap[dataItem.condition] : null;
    return dataItem;
});

// END SOLUTION

console.log(finalData);

我在这里错过了什么？

Answer 1

const rulesMap = conds.reduce((map, condition) => {
    map[condition.id] = condition.conditions.rules;
    return map;
}, {});

创建条件地图：

const finalData = data.map(dataItem => {
    dataItem.condition = dataItem.condition ? rulesMap[dataItem.condition] : null;
    return dataItem;
});

获取已更换条件规则的新数据列表：

data

Answer 2

使用forEach循环通过id数组获取conds然后使用find()过滤conditions.rules数组以获得相关的

data.forEach(function(item) {
    item.condition = conds.find(x => x.id === item.id).conditions.rules;
});

，如：

const data = [{
    id: 1,
    condition: 1,
    helpers: [{id: 1, condition: null}, {id: 2, condition: 2}]
  },{
    id: 2,
    condition: null,
    helpers: [{id: 1, condition: 1}, {id: 2, condition: null}]
}];

const conds = [{
    id: 1,
    conditions: {
       rules: ['test', 'foo']
    }
  },{
    id: 2,
    conditions: {
       rules: ['#hashtag', 'foo']
    }
}];

data.forEach(function(item) {
  item.condition = conds.find(x => x.id === item.id).conditions.rules;
});

console.log(data);

工作小提琴：

const finalData = data.map(dataItem => {
  dataItem.condition = dataItem.condition ? rulesMap[dataItem.condition] : null;
  dataItem.helpers.map(item => {
    item.condition = item.condition ? rulesMap[item.condition] : null
  })
  return dataItem;
});

Answer 3

搞定了：

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