在scatterplot3d底部绘制很长的图例

Question

如何正确地将很长的图例放在 scatterplot3d 图的底部？我尝试使用layout、oma、mar，但我无法弄清楚。我想要的是将情节放在顶部并将图例放在底部。我无法继续下去。我真的需要帮助:(

这是我迄今为止尝试过的代码：

library("scatterplot3d")


mean_E = c(2.5459233083,-1.75924812,-1.48706767,-1.70857143,-1.7201293233,2.1565954887,-1.3398496,3.353383,-0.96511278,2.81007519,0.8252120301,0.7203008,-1.2539834586,-1.5503759,0.67669,-0.0421053)
mean_P = c(1.02256,-1.744361,-1.56391,0.390977,-0.9819549,1.76015038,-1.962406,2.6294015038,0.526316,2.9744361,0.9172932,0.6315789,-0.6210526,0.93985,1.4208105263,0.406015)
mean_A = c(0.09023,-0.5714,-0.6165414,-0.428571,0.225564,0.80766917,-0.64180451,1.6967218045,-0.030075,2.6631579,0.5714286,0.1609023,-0.7487218,0.3619112782,1.7578947,0.3729323)
statementNameList = c("Sentence Sentence Sentence Sentence Sentence Sentence 1",
"Sentence Sentence Sentence Sentence Sentence Sentence 2",
"Sentence Sentence Sentence Sentence Sentence Sentence 3",
"Sentence Sentence Sentence Sentence Sentence Sentence 4",
"Sentence Sentence Sentence Sentence Sentence Sentence 5",
"Sentence Sentence Sentence Sentence Sentence Sentence 6",
"Sentence Sentence Sentence Sentence Sentence Sentence 7",
"Sentence Sentence Sentence Sentence Sentence Sentence 8",
"Sentence Sentence Sentence Sentence Sentence Sentence 9",
"Sentence Sentence Sentence Sentence Sentence Sentence 10",
"Sentence Sentence Sentence Sentence Sentence Sentence 11",
"Sentence Sentence Sentence Sentence Sentence Sentence 12",
"Sentence Sentence Sentence Sentence Sentence Sentence 13",
"Sentence Sentence Sentence Sentence Sentence Sentence 14",
"Sentence Sentence Sentence Sentence Sentence Sentence 15",
"Sentence Sentence Sentence Sentence Sentence Sentence 16")

mean_df <- data.frame("E"=mean_E,"P"=mean_P,"A"=mean_A,"Sentence"=statementNameList)

expressions <- data.frame("E"=c(-1.569,1.4796,-2.3793,3.4469,-2.4077, 2.8125,-2.5706,  3.0389,-2.09,-2.2676, -2.0267),
                          "P"=c(-1.1345,1.3151,-1.3414,2.9125,-0.7577, 2.2475,0.2676, 1.8417,-0.7833, -0.3514, 1.0667 ),
                          "A"=c(-2.0621,2.3139,-1.8759,0.2438,-0.6808, 2.16,0.4265, -2.7889,-2.19,0.7243,1.7967),
                          "Emotion"= c("Tired", "Surprised", "Sad", "Happy", "Fearful", "Excited", "Disgusted", "Calm", "Bored", "Annoyed", "Angry") )


title="EPA Ratings"
xlabel = "Evaluation (E)"
ylabel = "Potency (P)"
zlabel = "Activitiy (A)"
angle = -70


plot<-scatterplot3d(expressions$E ,expressions$P,expressions$A, main=title,
                    xlab=xlabel, ylab=ylabel, zlab=zlabel, pch = "", grid=TRUE, box=TRUE,
                    angle = angle)
plot$points3d(expressions$E ,expressions$P,expressions$A, pch = 5, col="red")

color_palette = grDevices::colors()[grep('gr(a|e)y', grDevices::colors(), invert = T)]
# select different color for each sentence
colors =sample(color_palette, 16)
plot$points3d(mean_df$E ,mean_df$P,mean_df$A, pch = 16, col=colors, cex=2)

legend(3,-3, legend = statementNameList,col = colors, pch = 16, inset = -0.5, cex = 0.7,
        bty = "n",xpd = TRUE)

text(plot$xyz.convert(expressions$E ,expressions$P,expressions$A-0.2), labels = expressions$Emotion, col = "darkblue", cex=0.6)

这是我当前的输出：

Answer 1

也许你可以尝试下面的代码。 我在这个链接中发现了这一点。 http://www.sthda.com/english/wiki/scatterplot3d-3d-graphics-r-software-and-data-visualization

自定义形状/颜色

s3d <- scatterplot3d(iris[,1:3], pch = shapes, color=colors)
legend("bottom", legend = levels(iris$Species),
      col =  c("#999999", "#E69F00", "#56B4E9"), 
      pch = c(16, 17, 18), 
      inset = -0.25, xpd = TRUE, horiz = TRUE)

Answer 2

用于 scatterplot3d 的 legend() 函数来自基础 R。因此您只需添加 cex <1 to it. If using CallBetterSaul's example, it will be like this:

s3d <- scatterplot3d(iris[,1:3], pch = shapes, color=colors)
legend("bottom", legend = levels(iris$Species),
  col =  c("#999999", "#E69F00", "#56B4E9"), 
  pch = c(16, 17, 18), 
  inset = -0.25, xpd = TRUE, horiz = TRUE, cex=.8)