我不明白这段代码有什么问题

Question

我在以下代码中遇到错误，但我不明白它出了什么问题。

我只是想学习如何做到这一点，这是一个测试。

我不知道出了什么问题或如何解决。

print "Would you like to see today's weather?"

answer = input

if answer = "yes":
    print "Follow Link: http://www.weather.com/weather/right-now/Yorktown+VA+23693 "
elif answer = "no":
    print "Very well, would you like to play a guessing game?"
    if answer = "yes":
        import random

        secret = random.randint (1, 99)
        guess= 0
        tries= 0

        print "AHOY!  I'm the Dread Pirate Roberts, and I have a secret!"
        print "It is a number from 1 to 99. I'll give you 6 tries. "

        while guess != secret and tries < 6:
            guess = input("What's your guess? ")
            if guess < secret:
                print "Too low, ye scurvy dog!"
            elif guess > secret:
                print "Too high, landlubber!"
            tries = tries + 1
            if guess == secret:
                print "Avast! Ye got it! Found my secret ye did!"
    elif answer = "no":
        print "Thank you, and goodnight."

Answer 1

第一个错误在这里：

if answer = "yes": #This would be giving you a syntax error

您想要做的是比较（代码中的每个测试用例都相同）：

if answer == "yes": #Notice the double equals to sign

---

另外，你想调用输入函数：

answer = input() #Notice the parentheses 

---

第三个 错误（这是逻辑错误）：

print "Very well, would you like to play a guessing game?"
#You are missing an input statemtent
if answer = "yes":

---

然后，同样的错误：

print "It is a number from 1 to 99. I'll give you 6 tries. "
#You are agin missing an input statement
while guess != secret and tries < 6:

Answer 2

除了 AshRj 指出的之外，这里还有两个更明显的错误：

answer = input

这会将实际函数“

input

”分配给

answer

，而不是调用该函数。另外，您可能想使用

raw_input

来代替。所以，使用

answer = raw_input()

。

elif answer = "no":
    print "Very well, would you like to play a guessing game?"
    if answer = "yes":

您没有在这些比较之间获取新答案，因此当您再次测试时，

answer

仍将是

no

。

Answer 3

我认为打印函数 print 应该用作：

print("any string")

不是：

print "any string"