我不能用多个语句来检查两个语句。

Question

我在python中做了一个代码，让密码并保存在文本文件中，如果用户在文件中输入了相同的密码，就会出现错误代码。问题是，虽然我做了两条语句来检查密码是否有效，并且在文本文件中没有相同的密码，但检查文本文件的语句却发现相同的文件。你能告诉我，我哪里出错了吗？

def InputString():
    String = str(input("Enter your password. :"))

    return String

def CheckPassword(Password):
    ##I declared "Index","Upper","Lower","Digit" and "Other" as Integer.
    ##In python, there is no data type for
    ##"char", so We use string instead.
    ##I use "variable" as boolean for checking password.
    Upper = 0
    Lower = 0
    Digit = 0
    Other = 0
    variable = False
    for index in range(len(Password)):

        NextChar = (Password[index:index+1])
        if NextChar >= "A" and NextChar <= "Z":
            Upper = Upper + 1
            elif NextChar >= "a" and NextChar <= "z":
            Lower = Lower + 1
        elif NextChar >= "0" and NextChar <= "9":
            Digit = Digit + 1
        else :
            Other = Other + 1

    if Upper > 1 and Lower >= 5 and (Digit - Other) > 0:
        variable = True
    else :
        variable = False

    return variable

def CheckThrough (Password):
    FileP = open("Password.txt","r")
    if FileP.mode == 'r':
        contents = FileP.read()
        if contents == Password:
            usable = False
        else :
             usable = True
    FileP.close()

    return usable


###The main programs starts here###

print("Enter the password.")
print("You must add at least 1 upper character.")
print("5 lower character")
print("and the difference between numeric character and symbols must be more than 1.")
variable = False
usable = False

while variable == False and usable == False:
    Password = InputString()
    variable = CheckPassword(Password)
    if variable == True:
        usable = CheckThrough(Password)
        if usable == True:
            print("You can use the password.")
        elif usable ==False :
            print("The password you entered is already used.")
        else :
            print("The error is ocuured.")
    else :
        print("You can't use this password, try again.")

print("Your password is",Password)

FileP = open("Password.txt","a+")
FileP.write(Password)
FileP.write("\n")
FileP.close()

Answer 1

你需要添加 .strip() 所以它没有空格，例如 String = str(input("Enter your password. :").strip()). 当你输入密码时，有一个空格，但它不会被保存到文件中，因此它总是把它作为一个新的密码来读取。

我的输入 = 输入你的密码。 :Kingdom1hearTs.

程序的输入="Kingdom1hearTs"

(用打印的方式查看输入系统的内容)

和 if contents == Password: 需要 if Password in contents:否则你看到的密码是否与整个txt文件相同。

NextChar = (Password[index:index+1])
        if NextChar >= "A" and NextChar <= "Z":
            Upper = Upper + 1
        elif NextChar >= "a" and NextChar <= "z": #had the wrong indentation
            Lower = Lower + 1
        elif NextChar >= "0" and NextChar <= "9":
            Digit = Digit + 1
        else :
            Other = Other + 1