给定一个信用卡号并且没有其他信息,PHP 中确定它是否是有效号码的最佳方法是什么?
现在我需要一些可以与美国运通卡、Discover、MasterCard 和 Visa 一起使用的东西,但如果它也可以与其他类型一起使用,可能会有帮助。
卡号验证分为三个部分:
大多数卡使用 Luhn 算法进行校验和:
维基百科链接上有许多实现的链接,包括 PHP:
<?
/* Luhn algorithm number checker - (c) 2005-2008 shaman - www.planzero.org *
* This code has been released into the public domain, however please *
* give credit to the original author where possible. */
function luhn_check($number) {
// Strip any non-digits (useful for credit card numbers with spaces and hyphens)
$number=preg_replace('/\D/', '', $number);
// Set the string length and parity
$number_length=strlen($number);
$parity=$number_length % 2;
// Loop through each digit and do the maths
$total=0;
for ($i=0; $i<$number_length; $i++) {
$digit=$number[$i];
// Multiply alternate digits by two
if ($i % 2 == $parity) {
$digit*=2;
// If the sum is two digits, add them together (in effect)
if ($digit > 9) {
$digit-=9;
}
}
// Total up the digits
$total+=$digit;
}
// If the total mod 10 equals 0, the number is valid
return ($total % 10 == 0) ? TRUE : FALSE;
}
?>
PHP 中不可缺少的 10 个正则表达式:
function check_cc($cc, $extra_check = false){
$cards = array(
"visa" => "(4\d{12}(?:\d{3})?)",
"amex" => "(3[47]\d{13})",
"jcb" => "(35[2-8][89]\d\d\d{10})",
"maestro" => "((?:5020|5038|6304|6579|6761)\d{12}(?:\d\d)?)",
"solo" => "((?:6334|6767)\d{12}(?:\d\d)?\d?)",
"mastercard" => "(5[1-5]\d{14})",
"switch" => "(?:(?:(?:4903|4905|4911|4936|6333|6759)\d{12})|(?:(?:564182|633110)\d{10})(\d\d)?\d?)",
);
$names = array("Visa", "American Express", "JCB", "Maestro", "Solo", "Mastercard", "Switch");
$matches = array();
$pattern = "#^(?:".implode("|", $cards).")$#";
$result = preg_match($pattern, str_replace(" ", "", $cc), $matches);
if($extra_check && $result > 0){
$result = (validatecard($cc))?1:0;
}
return ($result>0)?$names[sizeof($matches)-2]:false;
}
输入示例:
$cards = array(
"4111 1111 1111 1111",
);
foreach($cards as $c){
$check = check_cc($c, true);
if($check!==false)
echo $c." - ".$check;
else
echo "$c - Not a match";
echo "<br/>";
}
这给了我们
4111 1111 1111 1111 - 签证
最好不要在代码中进行验证。将卡信息直接发送到您的支付网关,然后处理他们的响应。如果您不先做 Luhn 检查之类的事情,它可以帮助他们检测欺诈行为 - 让他们看到失败的尝试。
PHP 代码
function validateCC($cc_num, $type) {
if($type == "American") {
$denum = "American Express";
} elseif($type == "Dinners") {
$denum = "Diner's Club";
} elseif($type == "Discover") {
$denum = "Discover";
} elseif($type == "Master") {
$denum = "Master Card";
} elseif($type == "Visa") {
$denum = "Visa";
}
if($type == "American") {
$pattern = "/^([34|37]{2})([0-9]{13})$/";//American Express
if (preg_match($pattern,$cc_num)) {
$verified = true;
} else {
$verified = false;
}
} elseif($type == "Dinners") {
$pattern = "/^([30|36|38]{2})([0-9]{12})$/";//Diner's Club
if (preg_match($pattern,$cc_num)) {
$verified = true;
} else {
$verified = false;
}
} elseif($type == "Discover") {
$pattern = "/^([6011]{4})([0-9]{12})$/";//Discover Card
if (preg_match($pattern,$cc_num)) {
$verified = true;
} else {
$verified = false;
}
} elseif($type == "Master") {
$pattern = "/^([51|52|53|54|55]{2})([0-9]{14})$/";//Mastercard
if (preg_match($pattern,$cc_num)) {
$verified = true;
} else {
$verified = false;
}
} elseif($type == "Visa") {
$pattern = "/^([4]{1})([0-9]{12,15})$/";//Visa
if (preg_match($pattern,$cc_num)) {
$verified = true;
} else {
$verified = false;
}
}
if($verified == false) {
//Do something here in case the validation fails
echo "Credit card invalid. Please make sure that you entered a valid <em>" . $denum . "</em> credit card ";
} else { //if it will pass...do something
echo "Your <em>" . $denum . "</em> credit card is valid";
}
}
使用方法
echo validateCC("1738292928284637", "Dinners");
更多理论信息可以在这里找到:
luhn 算法是一种校验和,可用于验证许多信用卡格式的格式(以及加拿大社会保险号码......)
维基百科文章还链接到许多不同的实现;这是一个 PHP 的:
http://planzero.org/code/bits/viewcode.php?src=luhn_check.phps
有一个 PEAR 包可以处理许多财务数字的验证,以及信用卡验证:http://pear.php.net/package/Validate_Finance_CreditCard
顺便说一句,这里有一些 PayPal 的测试信用卡帐号。
只需添加一些其他人可能会觉得有用的代码片段(不是 PHP 代码)。
PYTHON(单行代码;可能效率不高)
验证:
>>> not(sum(map(int, ''.join(str(n*(i%2+1)) for i, n in enumerate(map(int, reversed('1234567890123452'))))))%10)
True
>>> not(sum(map(int, ''.join(str(n*(i%2+1)) for i, n in enumerate(map(int, reversed('1234567890123451'))))))%10)
False
返回所需的校验位:
>>> (10-sum(map(int, ''.join(str(n*(i%2+1)) for i, n in enumerate(map(int, reversed('123456789012345')), start=1)))))%10
2
>>> (10-sum(map(int, ''.join(str(n*(i%2+1)) for i, n in enumerate(map(int, reversed('234567890123451')), start=1)))))%10
1
MySQL 函数
函数“ccc”和“ccd”(信用卡检查和信用卡数字)
请注意,“ccc”函数有一个额外的检查,如果计算出的总和为 0,则返回的结果将始终为 FALSE,因此全零的 CC 数字永远不会被验证为正确(在正常行为下,它将正确验证) 。该功能可以根据需要添加/删除;也许有用,具体取决于具体要求。
DROP FUNCTION IF EXISTS ccc;
DROP FUNCTION IF EXISTS ccd;
DELIMITER //
CREATE FUNCTION ccc (n TINYTEXT) RETURNS BOOL
BEGIN
DECLARE x TINYINT UNSIGNED;
DECLARE l TINYINT UNSIGNED DEFAULT length(n);
DECLARE i TINYINT UNSIGNED DEFAULT l;
DECLARE s SMALLINT UNSIGNED DEFAULT 0;
WHILE i > 0 DO
SET x = mid(n,i,1);
IF (l-i) mod 2 = 1 THEN
SET x = x * 2;
END IF;
SET s = s + x div 10 + x mod 10;
SET i = i - 1;
END WHILE;
RETURN s != 0 && s mod 10 = 0;
END;
CREATE FUNCTION ccd (n TINYTEXT) RETURNS TINYINT
BEGIN
DECLARE x TINYINT UNSIGNED;
DECLARE l TINYINT UNSIGNED DEFAULT length(n);
DECLARE i TINYINT UNSIGNED DEFAULT l;
DECLARE s SMALLINT UNSIGNED DEFAULT 0;
WHILE i > 0 DO
SET x = mid(n,i,1);
IF (l-i) mod 2 = 0 THEN
SET x = x * 2;
END IF;
SET s = s + x div 10 + x mod 10;
SET i = i - 1;
END WHILE;
RETURN ceil(s/10)*10-s;
END;
然后可以在 SQL 查询中直接使用函数:
mysql> SELECT ccc(1234567890123452);
+-----------------------+
| ccc(1234567890123452) |
+-----------------------+
| 1 |
+-----------------------+
1 row in set (0.00 sec)
mysql> SELECT ccc(1234567890123451);
+-----------------------+
| ccc(1234567890123451) |
+-----------------------+
| 0 |
+-----------------------+
1 row in set (0.00 sec)
mysql> SELECT ccd(123456789012345);
+----------------------+
| ccd(123456789012345) |
+----------------------+
| 2 |
+----------------------+
1 row in set (0.00 sec)
mysql> SELECT ccd(234567890123451);
+----------------------+
| ccd(234567890123451) |
+----------------------+
| 1 |
+----------------------+
1 row in set (0.00 sec)
https://github.com/sfyanbel/CreditCardValidation
使用这个包很简单
$testCreditCard = "43943418067844";
$ob = new CreditCard();
return $ob->getTypeCreditCard($testCreditCard);
您将得到预期的数据
['美国运通',1]、['Visa',2]、['万事达卡',3]、['发现',4]
这只是为了确保使用一些基本 RegEX 模式时数字有效。
注意,这不会检查号码是否被某人使用。
http://www.roscripts.com/How_to_validate_credit_card_numbers-106.html