SELECT users.name, users.registrationdate, users.city, users.status
FROM users, referrals
WHERE users.username= referrals.referrals AND referrals.username='user_name'
SELECT adearning, reffearning
FROM earnings WHERE usersname='user_name33'
如何组合这两个查询,就好像第一个查询条件不匹配并且不运行一样。那么第二个查询应该运行并在条件匹配时返回一些值
试试这个
$query1 = $this->db->query("SELECT users.name, users.registrationdate, users.city, users.status
FROM users, referrals
WHERE users.username = referrals.referrals AND referrals.username='user_name'")
$result1 = $query1->result_array();
$query2 = $this->db->query("SELECT adearning, reffearning FROM earnings WHERE usersname='user_name33' ")
$result2 = $query2->result_array();
$dataArray = array_merge($result1, $result2);
如果想检查结果,请在行尾添加此
print_r($dataArray);die;
在此,它将在一个数组中打印所有内容
示例
$result1 = array(
'0' => 'sjhccsd',
'1' => 'ddd',
'2' => 'df',
'3' => 'dfd',
);
$result2 = array(
'0' => 'sjhccsd',
'1' => 'ddd',
'2' => 'df',
'3' => 'dfd',
);
$dataArray = array_merge($result1, $result2);
print_r($dataArray);
输出:
Array ( [0] => sjhccsd [1] => ddd [2] => df [3] => dfd [4] => sjhccsd [5] => ddd [6] => df [7] => dfd )