如何直接从url读取文件

Question

url = 'https://cdn.wsform.com/wp-content/uploads/2021/05/currency.csv'

f = open(url, 'r')
print(f.read())

Invalid argument: 'https://cdn.wsform.com/wp-content/uploads/2021/05/currency.csv'

有什么方法可以让我从 url 读取文件，而不是下载它吗？？

Answer 1

是的，标准

urllib.request.urlopen()

正是这样做的：

from urllib import request

with request.urlopen('https://cdn.wsform.com/wp-content/uploads/2021/05/currency.csv') as f:
    print(f.read().decode())  # the decode turns the bytes into a string for printing

请注意，该文件是作为

bytes

文件打开的，因为该函数无法知道它是否是文本文件。