有没有更好的方式来获得通过lambda表达式传递时，属性名？这是我目前有。
例如。
GetSortingInfo<User>(u => u.UserId);
它的工作铸造它只有当财产是一个字符串memberexpression。因为并不是所有的属性都是字符串，我不得不使用对象，但随后会返回一个unaryexpression那些。
public static RouteValueDictionary GetInfo<T>(this HtmlHelper html,
Expression<Func<T, object>> action) where T : class
{
var expression = GetMemberInfo(action);
string name = expression.Member.Name;
return GetInfo(html, name);
}
private static MemberExpression GetMemberInfo(Expression method)
{
LambdaExpression lambda = method as LambdaExpression;
if (lambda == null)
throw new ArgumentNullException("method");
MemberExpression memberExpr = null;
if (lambda.Body.NodeType == ExpressionType.Convert)
{
memberExpr =
((UnaryExpression)lambda.Body).Operand as MemberExpression;
}
else if (lambda.Body.NodeType == ExpressionType.MemberAccess)
{
memberExpr = lambda.Body as MemberExpression;
}
if (memberExpr == null)
throw new ArgumentException("method");
return memberExpr;
}
我“米使用扩展方法用于预C＃6项目，并为那些靶向C＃6的nameof()。
public static class MiscExtentions
{
public static string NameOf<TModel, TProperty>(this object @object, Expression<Func<TModel, TProperty>> propertyExpression)
{
var expression = propertyExpression.Body as MemberExpression;
if (expression == null)
{
throw new ArgumentException("Expression is not a property.");
}
return expression.Member.Name;
}
}
我这样称呼它：
public class MyClass
{
public int Property1 { get; set; }
public string Property2 { get; set; }
public int[] Property3 { get; set; }
public Subclass Property4 { get; set; }
public Subclass[] Property5 { get; set; }
}
public class Subclass
{
public int PropertyA { get; set; }
public string PropertyB { get; set; }
}
// result is Property1
this.NameOf((MyClass o) => o.Property1);
// result is Property2
this.NameOf((MyClass o) => o.Property2);
// result is Property3
this.NameOf((MyClass o) => o.Property3);
// result is Property4
this.NameOf((MyClass o) => o.Property4);
// result is PropertyB
this.NameOf((MyClass o) => o.Property4.PropertyB);
// result is Property5
this.NameOf((MyClass o) => o.Property5);
它正常工作与两个字段和属性。
那么，有没有必要要求.Name.ToString()，但大致也差不多了，是的。您可能需要唯一要考虑的是x.Foo.Bar是否应该返回“富”，“酒吧”，或异常 - 即你需要在所有的迭代。
（重新注释）更灵活的排序，看here。
我上ObjectStateEntry创建扩展方法，以便能够标志属性（实体框架POCO类的），其改性的类型安全的方式中，由于默认的方法只接受一个字符串。这是我从属性获取名称的方法：
public static void SetModifiedProperty<T>(this System.Data.Objects.ObjectStateEntry state, Expression<Func<T>> action)
{
var body = (MemberExpression)action.Body;
string propertyName = body.Member.Name;
state.SetModifiedProperty(propertyName);
}
我已经做了类似下面的方法INotifyPropertyChanged实现。这里的属性存储在下面示出在基类的字典。当然，并不总是希望使用继承，但视图模型，我认为这是可以接受的，并给出了在视图模型类很干净属性引用。
public class PhotoDetailsViewModel
: PropertyChangedNotifierBase<PhotoDetailsViewModel>
{
public bool IsLoading
{
get { return GetValue(x => x.IsLoading); }
set { SetPropertyValue(x => x.IsLoading, value); }
}
public string PendingOperation
{
get { return GetValue(x => x.PendingOperation); }
set { SetPropertyValue(x => x.PendingOperation, value); }
}
public PhotoViewModel Photo
{
get { return GetValue(x => x.Photo); }
set { SetPropertyValue(x => x.Photo, value); }
}
}
在稍微更复杂的基类如下所示。它处理从lambda表达式属性名翻译。请注意，属性是真的假的属性，因为仅使用名字。但是它会出现透明的视图模型和参考的视图模型的属性。
public class PropertyChangedNotifierBase<T> : INotifyPropertyChanged
{
readonly Dictionary<string, object> _properties = new Dictionary<string, object>();
protected U GetValue<U>(Expression<Func<T, U>> property)
{
var propertyName = GetPropertyName(property);
return GetValue<U>(propertyName);
}
private U GetValue<U>(string propertyName)
{
object value;
if (!_properties.TryGetValue(propertyName, out value))
{
return default(U);
}
return (U)value;
}
protected void SetPropertyValue<U>(Expression<Func<T, U>> property, U value)
{
var propertyName = GetPropertyName(property);
var oldValue = GetValue<U>(propertyName);
if (Object.ReferenceEquals(oldValue, value))
{
return;
}
_properties[propertyName] = value;
RaisePropertyChangedEvent(propertyName);
}
protected void RaisePropertyChangedEvent<U>(Expression<Func<T, U>> property)
{
var name = GetPropertyName(property);
RaisePropertyChangedEvent(name);
}
protected void RaisePropertyChangedEvent(string propertyName)
{
if (PropertyChanged != null)
{
PropertyChanged(this, new PropertyChangedEventArgs(propertyName));
}
}
private static string GetPropertyName<U>(Expression<Func<T, U>> property)
{
if (property == null)
{
throw new NullReferenceException("property");
}
var lambda = property as LambdaExpression;
var memberAssignment = (MemberExpression) lambda.Body;
return memberAssignment.Member.Name;
}
public event PropertyChangedEventHandler PropertyChanged;
}
这是另一种答案：
public static string GetPropertyName<TModel, TProperty>(this HtmlHelper<TModel> htmlHelper,
Expression<Func<TModel, TProperty>> expression)
{
var metaData = ModelMetadata.FromLambdaExpression(expression, htmlHelper.ViewData);
return metaData.PropertyName;
}
如果你想获得数倍领域我离开这个功能：
/// <summary>
/// Get properties separated by , (Ex: to invoke 'd => new { d.FirstName, d.LastName }')
/// </summary>
/// <typeparam name="T"></typeparam>
/// <param name="exp"></param>
/// <returns></returns>
public static string GetFields<T>(Expression<Func<T, object>> exp)
{
MemberExpression body = exp.Body as MemberExpression;
var fields = new List<string>();
if (body == null)
{
NewExpression ubody = exp.Body as NewExpression;
if (ubody != null)
foreach (var arg in ubody.Arguments)
{
fields.Add((arg as MemberExpression).Member.Name);
}
}
return string.Join(",", fields);
}
这里是另一种方式来获得的PropertyInfo基于关闭this answer.它不需要一个对象实例的需要。
/// <summary>
/// Get metadata of property referenced by expression. Type constrained.
/// </summary>
public static PropertyInfo GetPropertyInfo<TSource, TProperty>(Expression<Func<TSource, TProperty>> propertyLambda)
{
return GetPropertyInfo((LambdaExpression) propertyLambda);
}
/// <summary>
/// Get metadata of property referenced by expression.
/// </summary>
public static PropertyInfo GetPropertyInfo(LambdaExpression propertyLambda)
{
// https://stackoverflow.com/questions/671968/retrieving-property-name-from-lambda-expression
MemberExpression member = propertyLambda.Body as MemberExpression;
if (member == null)
throw new ArgumentException(string.Format(
"Expression '{0}' refers to a method, not a property.",
propertyLambda.ToString()));
PropertyInfo propInfo = member.Member as PropertyInfo;
if (propInfo == null)
throw new ArgumentException(string.Format(
"Expression '{0}' refers to a field, not a property.",
propertyLambda.ToString()));
if(propertyLambda.Parameters.Count() == 0)
throw new ArgumentException(String.Format(
"Expression '{0}' does not have any parameters. A property expression needs to have at least 1 parameter.",
propertyLambda.ToString()));
var type = propertyLambda.Parameters[0].Type;
if (type != propInfo.ReflectedType &&
!type.IsSubclassOf(propInfo.ReflectedType))
throw new ArgumentException(String.Format(
"Expression '{0}' refers to a property that is not from type {1}.",
propertyLambda.ToString(),
type));
return propInfo;
}
它可以被称为像这样：
var propertyInfo = GetPropertyInfo((User u) => u.UserID);
我已经更新@Cameron's answer包括一些安全检查，对Convert类型的lambda表达式：
PropertyInfo GetPropertyName<TSource, TProperty>(
Expression<Func<TSource, TProperty>> propertyLambda)
{
var body = propertyLambda.Body;
if (!(body is MemberExpression member)
&& !(body is UnaryExpression unary
&& (member = unary.Operand as MemberExpression) != null))
throw new ArgumentException($"Expression '{propertyLambda}' " +
"does not refer to a property.");
if (!(member.Member is PropertyInfo propInfo))
throw new ArgumentException($"Expression '{propertyLambda}' " +
"refers to a field, not a property.");
var type = typeof(TSource);
if (!propInfo.DeclaringType.GetTypeInfo().IsAssignableFrom(type.GetTypeInfo()))
throw new ArgumentException($"Expresion '{propertyLambda}' " +
"refers to a property that is not from type '{type}'.");
return propInfo;
}
在.NET 4.0中，您可以使用ExpressionVisitor找到性能开始：
class ExprVisitor : ExpressionVisitor {
public bool IsFound { get; private set; }
public string MemberName { get; private set; }
public Type MemberType { get; private set; }
protected override Expression VisitMember(MemberExpression node) {
if (!IsFound && node.Member.MemberType == MemberTypes.Property) {
IsFound = true;
MemberName = node.Member.Name;
MemberType = node.Type;
}
return base.VisitMember(node);
}
}
这里是你如何使用这个访问者：
var visitor = new ExprVisitor();
visitor.Visit(expr);
if (visitor.IsFound) {
Console.WriteLine("First property in the expression tree: Name={0}, Type={1}", visitor.MemberName, visitor.MemberType.FullName);
} else {
Console.WriteLine("No properties found.");
}