我有这个问题:
SELECT
c.br,
c.no_,
CONCAT(c.name, ' ', c.surname) AS Name,
t.type,
t.code,
t.sub,
GETDATE() AS date,
c2.name
FROM
c
INNER JOIN t on c.rowno = t.rowno
LEFT JOIN termjnt on t.rowno = termjnt.rowno
LEFT JOIN c c2 on termjnt.rowno_c2 = c2.rowno
WHERE
t.status = 'active'
这是一个输出示例
如何为每个no_组合c2.name行?例如,我不希望Heather和Humphry成为不同的行,而是希望单元格成为“Humphry,Heather”