散点图的轴限制 - Matplotlib

问题描述 投票:0回答:2

我遇到了同样的问题here,但是,所提出的解决方案对我不起作用。

我正在绘制一组数据,其主图具有以下模式:

enter image description here

这是一个图,其轴限制在 x 和 y 上都从 (-1, 1) 变化,并使用这段代码设置了边距:

plt.figure()
plt.show(data)
## Add some margin
l, r, b, t = plt.axis()
dx, dy = r-l, t-b
plt.axis([l-0.1*dx, r+0.1*dx, b-0.1*dy, t+0.1*dy])

问题是因为我有更“复杂”的情节,其中我必须做出一些改变。这是生成它的代码:

def plot_quiver_singularities(min_points, max_points, vector_field_x, vector_field_y, file_path):
    """
    Plot the singularities of vector field
    :param file_path : the path to save the data
    :param vector_field_x : the vector field x component to be plot
    :param vector_field_y : the vector field y component to be plot
    :param min_points : a set (x, y) of min points field
    :param max_points : a set (x, y) of max points  field
    """
    fig = plt.figure(figsize=(8, 8))
    ax = fig.add_axes([.13, .3, .6, .6])
    
    ## Plot quiver
    x, y = numpy.mgrid[-1:1:100*1j, -1:1:100*1j]
    m = numpy.sqrt(numpy.power(vector_field_x, 2) + numpy.power(vector_field_y, 2))
    quiver = ax.quiver(x, y, vector_field_x, vector_field_y, m, zorder=1)
    
    ## Plot critical points
    x = numpy.linspace(-1, 1, x_steps)
    y = numpy.linspace(-1, 1, y_steps)
    
    # Draw the min points
    x_indices = numpy.nonzero(min_points)[0]
    y_indices = numpy.nonzero(min_points)[1]
    ax.scatter(x[x_indices], y[y_indices], marker='$\\circlearrowright$', s=100, zorder=2)
    
    # Draw the max points
    x_indices = numpy.nonzero(max_points)[0]
    y_indices = numpy.nonzero(max_points)[1]
    ax.scatter(x[x_indices], y[y_indices], marker='$\\circlearrowleft$', s=100, zorder=2)
    
    ## Put legends
    marker_min = plt.Line2D((0, 0), (0, 0), markeredgecolor=(1.0, 0.4, 0.0), linestyle='',
                            marker='$\\circlearrowright$', markeredgewidth=1, markersize=10)
    marker_max = plt.Line2D((0, 0), (0, 0), markeredgecolor=(0.2, 0.2, 1.0), linestyle='',
                            marker='$\\circlearrowleft$', markeredgewidth=1, markersize=10)
    plt.legend([marker_min, marker_max], ['CW rot. center', 'CCW rot. center'], numpoints=1,
               loc='center left', bbox_to_anchor=(1, 0.5))
    
    quiver_cax = fig.add_axes([.13, .2, .6, .03])
    fig.colorbar(quiver, orientation='horizontal', cax=quiver_cax)
    
    ## Set axis limits
    plt.xlim(-1, 1)
    plt.ylim(-1, 1)
    
    ## Add some margin
    # l, r, b, t = plt.axis()
    # dx, dy = r-l, t-b
    # plt.axis([l-0.1*dx, r+0.1*dx, b-0.1*dy, t+0.1*dy])
    
    plt.savefig(file_path + '.png', dpi=dpi)
    plt.close()

这会产生以下图像:

enter image description here

可以看出,轴限制不成立,我还没有找到原因。

python matplotlib plot limit
2个回答
48
投票

我能够解决放置这段代码的问题

plt.xlim(-1, 1)
plt.ylim(-1, 1)

打电话后就

scatter()


12
投票

您还可以将它们设置为

ax
对象:

ax.set_xlim((-1,1))
ax.set_ylim((-1,1))
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