我有一个与此类似的对象数组:
arr = [{ val: 1, ts : 123},{val: 2, ts : 125},{val: 3,ts : 120}, {val: 4, ts : 113} , {val:5, ts : 117},{ val: 6, ts : 143},{val: 7, ts : 193},{val: 8, ts : 187}, {val: 9, ts : 115} , {val:10,ts : 116}]
数组的长度始终是偶数。现在基本上我想将它们分成两半。
split1 = [{ val: 1, ts : 123},{val: 2, ts : 125},........,{val:5, ts : 117}]
split2 = [{ val: 6, ts : 143},{val: 7, ts : 193},........,{val:10,ts : 116}]
我必须映射这些数组并转换它们的字段(array1的第一项和array2的第一项,依此类推)。假设第一个数组的对象具有(键val和ts)的对象称为“旧”数组,第二个数组的对象具有(键val和ts的键)对象称为“新”数组。因此,我将它们映射了,最终应该看起来像这样
final = [
{ oldVal:1, oldts: 123 , newVal:6, newts: 143},
{ oldVal:2, oldts: 125 , newVal:7, newts: 193},
{ oldVal:3, oldts: 120 , newVal:8, newts: 187},
{ oldVal:4, oldts: 113 , newVal:9, newts: 115},
{ oldVal:5, oldts: 117 , newVal:10, newts: 116},
]
我尝试过的是:
var res= a.splice(0, arr.length/2);
var c = a.map((val, ind) => { {val, res[ind]} })
有人可以在这里指导吗?
i
个元素和第i + half
个作为其对: const arr = [{ val: 1, ts : 123},{val: 2, ts : 125},{val: 3,ts : 120}, {val: 4, ts : 113} , {val:5, ts : 117},{ val: 6, ts : 143},{val: 7, ts : 193},{val: 8, ts : 187}, {val: 9, ts : 115} , {val:10,ts : 116}];
const final = [];
const half = arr.length / 2;
for (let i = 0; i < half; i++) {
final.push({
oldVal: arr[i].val,
oldTs: arr[i].ts,
newVal: arr[i + half].val,
newTs: arr[i + half].ts,
});
}
console.log(final);
arr = [{ val: 1, ts : 123},{val: 2, ts : 125},{val: 3,ts : 120}, {val: 4, ts : 113} , {val:5, ts : 117},{ val1: 6, ts : 143},{val1: 7, ts : 193},{val1: 8, ts : 187}, {val1: 9, ts : 115} , {val1:10,ts : 116}];
let final = [];
arr.forEach(function(v, i) {
if (i >= arr.length / 2) return false;
final[i] = {oldVal: v.val, oldTs: v.ts, newVal: arr[i + arr.length / 2].val1, newTs: arr[i + arr.length / 2].ts}
});
console.log(final)