#include<stdio.h>
int main(){
float a[100],sum=0.0,avg,havg[100],min,max;
int i;
for(i=0; i!=-1;i++){
printf("Enter number : ");
scanf("%f",&a[i]);
max = a[0];
min = a[0];
sum+=a[i];
avg= sum/(i+1);
havg[i]=avg/2;
printf("Loop %d Summation : %.0f ",i,sum);
printf("Half of Avg. : %.2f \n",havg[i]);
for(int j=0; j<i; j++){
if (a[i]>max) {
max = a[i];
}
if (a[i]<min) {
min = a[i];
}
}
if(a[i]>havg[i-1]&&i!=0){
break;
}
}
printf("---Data Complete---\n");
printf("Max: %.0f\n", max);
printf("Min: %.0f\n", min);
这里的输出是:
输入数字:24
循环0求和:24平均一半:12.00
输入数字:12
循环1总和:36平均一半:9.00
输入数字:-5
循环2总和:31平均一半:5.17
输入数字:9
循环3求和:40平均一半:5.00
---数据完整---
马克斯:24
敏:9
我已经在google上查找数组中的最小值和最大值。我想我搞砸了一些东西:
#include<stdio.h>
int main(){
float a[100],sum=0.0,avg,havg[100],min=0.0,max=0.0;
int i;
for(i=0; i!=-1;i++){
printf("Enter number : ");
scanf("%f",&a[i]);
max = a[0];
min = a[0];
sum+=a[i];
avg= sum/(i+1);
havg[i]=avg/2;
printf("Loop %d Summation : %.0f ",i+1,sum);
printf("Half of Avg. : %.2f \n",havg[i]);
if (a[i]>max){
max = a[i];
}
if (a[i]<min){
min = a[i];
}
if(a[i]>havg[i-1]&&i!=0){
break;
}
}
printf("---Data Complete---\n");
printf("Max: %.0f\n", max);
printf("Min: %.0f\n", min);
}
所以现在我用不同的数字进行测试(从负数开始)
Enter number : -10
Loop 1 Summation : -10 Half of Avg. : -5.00
Enter number : -90
Loop 2 Summation : -100 Half of Avg. : -25.00
Enter number : 30
Loop 3 Summation : -70 Half of Avg. : -11.67
---Data Complete---
Max: 30
Min: -10
这真令人困惑