转换字符串

Question

我需要接受以下字符串并将其放入类型集合中并将其传递给过程

String Cars = Dodge Charger||Ford Mustang||Chevy Camro||Ford GT
String Cost = 35,000||25,000||29,000|55,000
String CarDesc = Power House||Sweet Ride||Too Cool||Blow your door off

我如何转换记录，使它们类似于以下内容？

 Cars:
  Dodge Charger||35,000||Power House
  Ford Mustang||25,00||Sweet Ride
  Chevy Camro||29,000||Too Cool
  Ford GT||55,000||Blow your door off

如何将它们解析为数组？

 Types
  create or replace TYPE             "CAR_IN_ARR"                                          
  IS
   TABLE OF CAR_OBJ

 create or replace TYPE             "CAR_OBJ"                                          
  AS
  OBJECT (CAR_NAME VARCHAR2 (50),
       Price    Number,
       CarDesc VARCHAR2 (100))

  procedure car_values (
      p_in_upd_car              car_in_arr,
      p_out_upd_results    out  car_out_cur
  )
  as

我尝试了各种for循环，但无法以正确的顺序获得它

非常感谢

Answer 1

双定界符||使此操作变得很困难，因此我用~替换了它们。也许有一种更整洁的方法可以使用单个正则表达式来处理此问题，或者可以使用substr和instr进行更精细的处理。

而且我还假设cost示例应为35,000||25,000||29,000||55,000。

实际代码可能应该验证所有字符串都包含相同数量的定界符。

declare
    inCars    long := 'Dodge Charger||Ford Mustang||Chevy Camro||Ford GT';
    inCost    long := '35,000||25,000||29,000||55,000';
    inCarDesc long := 'Power House||Sweet Ride||Too Cool||Blow your door off';

    type varchar2_tt is table of varchar2(50);
    type number_tt   is table of number;

    cars      varchar2_tt := varchar2_tt();
    costs     varchar2_tt := varchar2_tt();
    carDescs  varchar2_tt := varchar2_tt();
begin
    inCars := replace(inCars,'||','~');
    inCost := replace(inCost,'||','~');
    inCarDesc := replace(inCarDesc,'||','~');

    cars.extend(regexp_count(inCars,'~') +1);
    costs.extend(regexp_count(inCost,'~') +1);
    carDescs.extend(regexp_count(inCarDesc,'~') +1);

    for i in 1..cars.count loop
        cars(i) := regexp_substr(inCars,'[^~]+', 1, i);
        costs(i) := regexp_substr(inCost,'[^~]+', 1, i);
        carDescs(i) := regexp_substr(inCarDesc,'[^~]+', 1, i);

        dbms_output.put_line(cars(i) || '||' || costs(i) || '||' || carDescs(i));
    end loop;
end;