我正在按照发现的示例here进行绘图
[不幸的是,我需要显示17条曲线,图例与它们重叠。我知道我可以创建一个图例对象,该图例对象可以像here一样显示在绘图区域之外,但是我有17条曲线,因此使用循环要方便得多。
您知道如何结合这两种方法吗?
import pandas as pd
from bokeh.palettes import Spectral4
from bokeh.plotting import figure, output_file, show
from bokeh.sampledata.stocks import AAPL, IBM, MSFT, GOOG
from bokeh.models import Legend
from bokeh.io import output_notebook
output_notebook()
p = figure(plot_width=800, plot_height=250, x_axis_type="datetime", toolbar_location='above')
p.title.text = 'Click on legend entries to mute the corresponding lines'
legend_it = []
for data, name, color in zip([AAPL, IBM, MSFT, GOOG], ["AAPL", "IBM", "MSFT", "GOOG"], Spectral4):
df = pd.DataFrame(data)
df['date'] = pd.to_datetime(df['date'])
c = p.line(df['date'], df['close'], line_width=2, color=color, alpha=0.8,
muted_color=color, muted_alpha=0.2)
legend_it.append((name, [c]))
legend = Legend(items=legend_it)
legend.click_policy="mute"
p.add_layout(legend, 'right')
show(p)
from bokeh.models import CategoricalColorMapper, Legend
from bokeh.palettes import Category10
from bokeh.plotting import figure, show
from bokeh.sampledata.iris import flowers
color_mapper = CategoricalColorMapper(
factors=[x for x in flowers['species'].unique()], palette=Category10[10])
p = figure(height=350, width=500)
p.add_layout(Legend(), 'right')
p.circle("petal_length", "petal_width", source=flowers, legend_group='species',
color=dict(field='species', transform=color_mapper))
show(p)