ggplot比例尺x轴以立方为单位

Question

我想通过定义一个新函数来将x轴缩放为立方正方形。

cuberoot_trans = function(){
 trans = function(x) x^(1/3)
 }

ggplot(data = diamonds, aes(x=carat, y=price)) + 
 geom_point(alpha=1.5, size=0.75, position = 'jitter') +
 scale_x_continuous(breaks = c(0.2, 0.5, 1, 2, 3), limits = c(0.2, 3), trans = cuberoot_trans()) 

paste0（x，“ _trans”）中的错误：无法将类型'closure'强制转换为类型'character'的向量]

我在做什么错？