使用问题应该在CsvHelper中引用

问题描述 投票:0回答:2

我使用csvHelper库面临一些问题。我附上了我的班级对象。我希望字符串和dateTime类型的数据只会被引用。

我知道我需要更新csv.Configuration.ShouldQuote选项。但不知道怎么做。

static void Main()
        {      
            var recordNew = new List<Metadata>
             {
                 new Metadata { Id = Guid.NewGuid(), VersionNumber = 100, CreatedOn=DateTime.Now, Name = "two", AccountSequene=90, IsPublic=false}
             };

            writeDataTest(recordNew);

        }

        private static void writeDataTest(List<Metadata> records)
        {
            using (var writer = new StringWriter())
            using (var csv = new CsvWriter(writer))
            {
               csv.Configuration.HasHeaderRecord = false;
               csv.Configuration.ShouldQuote = (field, context) =>
               {
                    return context.Record.Count == 1;
                };
               csv.Configuration.RegisterClassMap<MetadataMap>();
               csv.WriteRecords(records);
               var s = writer.ToString();

            }
        }


        public class Metadata
        {
            public Guid? Id { get; set; }
            public long? VersionNumber { get; set; }
            public DateTime? CreatedOn { get; set; }
            public string Name { get; set; }
            public string Email { get; set; }
            public long? AccountSequene { get; set; }
            public bool? IsPublic { get; set; }
        }
        public class MetadataMap : ClassMap<Metadata>
        {
            public MetadataMap()
            {
                Map(m => m.Id).Index(0);
                Map(m => m.VersionNumber).Index(1);
                Map(m => m.CreatedOn).Index(2).ConvertUsing(m => $"\"{m.CreatedOn}\"");
                Map(m => m.Name).Index(3).ConvertUsing(m => $"\"{m.Name}\"");
                Map(m => m.Email).Index(4).ConvertUsing(m => $"\"{m.Email}\"");
                Map(m => m.AccountSequene).Index(5);
                Map(m => m.IsPublic).Index(6);
            }
        }

目前我得到的结果是

74d5c276-0e5f-442b-a392-cd8fb37c4114,“100”,“4/12/2019 2:11:40 PM”,“two”,“”,90,False

引用100作为我设置的返回context.Record.Count == 1;但我的预期结果是

74d5c276-0e5f-442b-a392-cd8fb37c4114,100,“4/12/2019 2:11:40 PM”,“two”,, 90,False

在预期的结果,因为没有提供字符串电子邮件所以我想要它(“两个”,90而不是“两个”,“”,90)

c# quote csvhelper
2个回答
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