给定一个点(x,y)列表,创建一个彼此不相近的点的新列表

问题描述 投票:0回答:2

我需要帮助,因为我是初学者:给出x,y点列表

list=  [(788, 117), (788, 118), (516, 164), (799, 171), (453, 225), (740, 284), (741, 284), (397, 329), (397, 330), (568, 338), (788, 117), (788, 118), (516, 164), (799, 171), (453, 225), (740, 284), (741, 284), (397, 329), (397, 330), (568, 338), (418, 112), (418, 113), (516, 164), (799, 171), (453, 225), (740, 284), (741, 284), (397, 329), (397, 330), (568, 338), (418, 112), (418, 113), (516, 164), (799, 171), (453, 225), (740, 284), (741, 284), (397, 329), (397, 330), (568, 338), (418, 112)

我想创建一个新的列表,其中的点彼此不相近。示例(788,117),(788,118)彼此接近。

我认为这个函数有助于找到欧几里德距离:

def dist(p, q):
    "Return the Euclidean distance between points p and q."
    return int(math.hypot(p[0] - q[0], p[1] - q[1]))

先感谢您

更新:

这是我尝试过的,它不符合我的要求:

import math

list1 = [(788, 117), (788, 118), (516, 164), (799, 171), (453, 225), (740, 284), (741, 284), (397, 329), (397, 330),
         (568, 338), (788, 117), (788, 118), (516, 164), (799, 171), (453, 225), (740, 284), (741, 284), (397, 329),
         (397, 330), (568, 338), (418, 112), (418, 113), (516, 164), (799, 171), (453, 225), (740, 284), (741, 284),
         (397, 329), (397, 330), (568, 338), (418, 112), (418, 113), (516, 164), (799, 171), (453, 225), (740, 284),
         (741, 284), (397, 329), (397, 330), (568, 338), (418, 112)]
list2 = []


def dist(p, q):
    "Return the Euclidean distance between points p and q."
    return int(math.hypot(p[0] - q[0], p[1] - q[1]))


while True:

    for i in list1:
        for j in list1:
            if i not in list2 and dist(i, j) <= 5:
                list2.append(i)

    print("list1 ", list1)
    print("list2 ", list2)

结果:如果更多的列表中没有重复点,那么它似乎变得更具挑战性

list1  [(788, 117), (788, 118), (516, 164), (799, 171), (453, 225), (740, 284), (741, 284), (397, 329), (397, 330), (568, 338), (788, 117), (788, 118), (516, 164), (799, 171), (453, 225), (740, 284), (741, 284), (397, 329), (397, 330), (568, 338), (418, 112), (418, 113), (516, 164), (799, 171), (453, 225), (740, 284), (741, 284), (397, 329), (397, 330), (568, 338), (418, 112), (418, 113), (516, 164), (799, 171), (453, 225), (740, 284), (741, 284), (397, 329), (397, 330), (568, 338), (418, 112)]
list2  [(788, 117), (788, 118), (516, 164), (799, 171), (453, 225), (740, 284), (741, 284), (397, 329), (397, 330), (568, 338), (418, 112), (418, 113)]

列表不断更新,这就是为什么我有一个while循环我在这里做错了什么

更新:

points =  [(336, 14), (335, 15), (336, 15), (337, 15), (524, 15), (525, 15), (526, 15), (335, 16), (336, 16), (337, 16),
           (525, 16), (526, 16), (336, 17), (706, 19), (705, 20), (706, 20), (707, 20), (705, 21), (706, 21), (707, 21),
           (706, 22), (434, 66), (433, 67), (434, 67), (435, 67), (433, 68), (434, 68), (435, 68), (717, 73), (718, 73),
           (716, 74), (717, 74), (718, 74), (717, 75), (718, 75), (370, 127), (371, 127), (372, 127), (370, 128),
           (371, 128), (372, 128), (371, 129), (600, 129), (601, 129), (602, 129), (601, 130), (602, 130), (485, 140),
           (486, 140), (390, 174), (391, 174), (392, 174), (390, 175), (391, 175), (392, 175), (658, 186), (659, 186),
           (658, 187), (659, 187), (660, 187), (658, 188), (659, 188), (660, 188), (315, 231), (314, 232), (315, 232),
           (316, 232), (314, 233), (315, 233), (316, 233), (485, 240), (486, 240), (487, 240), (485, 241), (486, 241),
           (487, 241), (485, 242), (486, 242), (665, 250), (666, 250), (645, 339), (646, 339), (593, 384), (594, 384),
           (595, 384), (596, 384), (593, 385), (594, 385), (595, 385), (710, 386), (711, 386), (709, 387), (710, 387),
           (711, 387), (712, 387), (709, 388), (710, 388), (711, 388), (712, 388)]
python list distance points closest
2个回答
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