Quartz.NET来自ASP.NET中的config.xml

问题描述 投票:5回答:1

有人可以告诉我我做错了什么。我正在尝试设置石英,以便在启动时它将读取xml配置文件。在文件内部有一个激活我的HelloEmail_Job.cs类的作业(它被正确创建,使用execute方法中的逻辑扩展IJob)。 xml还有一个cron触发器,用于每分钟触发的作业(纯粹用于测试)。

但是一切都没有错误地启动,但工作永远不会发生。我确信我配置错误。

我有一个处理我的调度程序生成的单例,调度程序在我的应用程序启动时启动(在global.asax文件中)

    NameValueCollection properties = new NameValueCollection();
    properties["quartz.scheduler.instanceName"] = "RemoteServer";

    ////// set thread pool info
    properties["quartz.threadPool.type"] = "Quartz.Simpl.SimpleThreadPool, Quartz";
    properties["quartz.threadPool.threadCount"] = "5";
    properties["quartz.threadPool.threadPriority"] = "Normal";

    properties["quartz.jobStore.type"] = "Quartz.Impl.AdoJobStore.JobStoreTX, Quartz";
    properties["quartz.jobStore.useProperties"] = "true";
    properties["quartz.jobStore.dataSource"] = "default";
    properties["quartz.jobStore.tablePrefix"] = "QRTZ_";
    properties["quartz.jobStore.lockHandler.type"] = "Quartz.Impl.AdoJobStore.UpdateLockRowSemaphore, Quartz";

    properties["quartz.dataSource.default.connectionString"] = "Data Source=CRAIG-PC\\SQLEXPRESS;Initial Catalog=MCWdb;User ID=sa;Password=mastercrud;";
    properties["quartz.dataSource.default.provider"] = "SqlServer-20";

    // job initialization plugin handles our xml reading, without it defaults are used
    properties["quartz.plugin.xml.type"] = "Quartz.Plugin.Xml.XMLSchedulingDataProcessorPlugin, Quartz";
    properties["quartz.plugin.xml.fileNames"] = "~/quartz_jobs.xml";

    ISchedulerFactory sf = new StdSchedulerFactory(properties);
    _sched = sf.GetScheduler();

我的quartz_jobs.xml文件看起来像这样:

        <?xml version="1.0" encoding="UTF-8"?>

        <job-scheduling-data xmlns="http://quartznet.sourceforge.net/JobSchedulingData"
                xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
                        version="2.0">

          <processing-directives>
            <overwrite-existing-data>true</overwrite-existing-data>
          </processing-directives>

          <schedule>        
                <job> 
                  <job-detail> 
                    <name>MyJob</name> 
                    <group>MyJobs</group> 
                    <description>sends out a test email</description>
                      <job-type>HelloEmail_Job</job-type>
                      <volatile>false</volatile> 
                    <durable>true</durable> 
                    <recover>false</recover> 
                    <job-data-map> 
                      <entry> 
                        <key>Body</key> 
                        <value>Hello From your website!!!!!!!!</value> 
                      </entry> 
                    </job-data-map> 
                  </job-detail> 
                  <trigger> 
                    <cron> 
                      <name>MyJobTrigger</name> 
                      <group>MyJobs</group> 
                      <description>A description</description> 
                      <job-name>MyJob</job-name> 
                      <job-group>MyJobs</job-group> 
                      <cron-expression>0 0/1 * 1/1 * ? *</cron-expression> 
                    </cron> 
                  </trigger> 
                </job>
            </schedule>

        </job-scheduling-data>

我知道调度程序正在为具有简单触发器的临时作业正确运行,因为当我的应用程序创建它们并动态调度它时,它可以完美地工作。但我希望逻辑可重复(通过cron),并可通过xml进行配置。

我的直觉是JOB_TYPE值是错误的。

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