我怎样才能从Internet Protocol version 4获得Dns.GetHostAddresses()
地址?我有下面的代码,它给我IPv4和IPv6地址。我必须使用具有多个IPv4地址的盒子。
IPAddress[] localIPs = Dns.GetHostAddresses(Dns.GetHostName());
private void get_IPs()
{
foreach (IPAddress a in localIPs)
{
server_ip = server_ip + a.ToString() + "/";
}
}
这是我的代码。并且可以在许多LAN卡上找到它。
private string GetLocalIpAddress()
{
string localIpAddress = string.Empty;
NetworkInterface[] nics = NetworkInterface.GetAllNetworkInterfaces();
foreach (NetworkInterface nic in nics)
{
if (nic.OperationalStatus != OperationalStatus.Up)
{
continue;
}
IPv4InterfaceStatistics adapterStat = (nic).GetIPv4Statistics();
UnicastIPAddressInformationCollection uniCast = (nic).GetIPProperties().UnicastAddresses;
if (uniCast != null)
{
foreach (UnicastIPAddressInformation uni in uniCast)
{
if (adapterStat.UnicastPacketsReceived > 0
&& adapterStat.UnicastPacketsSent > 0
&& nic.NetworkInterfaceType != NetworkInterfaceType.Loopback)
{
if (uni.Address.AddressFamily == AddressFamily.InterNetwork)
{
localIpAddress = nic.GetIPProperties().UnicastAddresses[0].Address.ToString();
break;
}
}
}
}
}
return localIpAddress;
}
以下是使用for循环查找第一个连接的IPv4的代码:
IPAddress ipAddress = null;
IPAddress[] localIPs = Dns.GetHostAddresses(Dns.GetHostName());
for (int i=0 ; i<localIPs.Length ; i++)
{
if (localIPs[i].AddressFamily == AddressFamily.InterNetwork)
{
ipAddress = localIPs[i];
break;
}
}
这是我使用的一个功能:
public static string GetIP4Address()
{
string IP4Address = String.Empty;
foreach (IPAddress IPA in Dns.GetHostAddresses(Dns.GetHostName()))
{
if (IPA.AddressFamily == AddressFamily.InterNetwork)
{
IP4Address = IPA.ToString();
break;
}
}
return IP4Address;
}
作为一个可枚举的:
public static IEnumerable<string> GetIP4Addresses()
{
return Dns.GetHostAddresses(Dns.GetHostName())
.Where(IPA => IPA.AddressFamily == AddressFamily.InterNetwork)
.Select(x => x.ToString());
}
使用Linq时非常干净和甜美
IPAddress[] addresses = Dns.GetHostAddresses(Dns.GetHostName()).Where(a => a.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork).ToArray();
写locaIPs.Where(ip => ip.AddressFamily == AddressFamily.InterNetwork)
来自MSDN on Dns.GetHostAddresses,
当空字符串作为主机名传递时,此方法返回除Windows Server 2003以外的所有操作系统的本地主机的IPv4地址。对于Windows Server 2003,将返回本地主机的IPv4和IPv6地址。
如果本地计算机未安装IPv6,则会从GetHostAddresses方法的结果中过滤IPv6地址。因此,如果只有IPv6结果可用于hostNameOrAddress.parameter,则可以返回空的IPAddress实例。
所以,你可以用它来try and parse it:
IPAddress.TryParse
然后检查AddressFamily
哪个
返回IPv4的System.Net.Sockets.AddressFamily.InterNetwork或IPv6的System.Net.Sockets.AddressFamily.InterNetworkV6。
string input = "192.168.0.10";
IPAddress address;
if (IPAddress.TryParse(input, out address))
{
switch (address.AddressFamily)
{
case System.Net.Sockets.AddressFamily.InterNetwork:
// we have IPv4
break;
case System.Net.Sockets.AddressFamily.InterNetworkV6:
// we have IPv6
break;
default:
// do something else
break;
}
}
我用了开头的答案
/// <summary> and it mostly worked:
//for some reason Visual Studio 2010 did not understand AddressFamily.Inernetwork
if (address.Address.AddressFamily != AddressFamily.InterNetwork)
我不得不使用:
if(address.Address.AddressFamily != System.Net.Sockets.AddressFamily.InterNetwork)
但我实际使用过:
if(!address.Address.AddressFamily.Equals(System.Net.Sockets.AddressFamily.InterNetwork))
另外,我补充说:
if (network.OperationalStatus != OperationalStatus.Up)
continue;
因为有些网络不起作用而且不应该在那里,我确实看到它们在注册表中。 ---阿尔文
我使用这个帮助方法,在过滤掉IPV6和Loopback一次后返回第一个活动的IPV4地址
public static IPAddress GetLocalIPAddress()
{
IPAddress result = null;
IPHostEntry iphostentry = Dns.GetHostEntry(Dns.GetHostName());
IPAddress[] ipv4Address = Array.FindAll(iphostentry.AddressList, add => add.AddressFamily == AddressFamily.InterNetwork && !IPAddress.IsLoopback(add));
if (ipv4Address.Length > 0 )
{
result =ipv4Address[0];
}
return result;
}
对我来说,更清洁的解决方案是:
public static string GetLocalIP()
{
string ipv4Address = String.Empty;
foreach (IPAddress currentIPAddress in Dns.GetHostAddresses(Dns.GetHostName()))
{
if (currentIPAddress.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork)
{
ipv4Address = currentIPAddress.ToString();
break;
}
}
return ipv4Address;
}