AngularJS将数据传递给$ http.get请求

Question

我有一个执行http POST请求的函数。代码如下所示。这很好用。

 $http({
   url: user.update_path, 
   method: "POST",
   data: {user_id: user.id, draft: true}
 });

我有另一个http GET函数，我想发送数据到该请求。但我没有这个选择。

 $http({
   url: user.details_path, 
   method: "GET",
   data: {user_id: user.id}
 });

http.get的语法是

get（url，config）

Answer 1

从AngularJS v1.4.8开始，您可以使用get(url, config)，如下所示：

var data = {
 user_id:user.id
};

var config = {
 params: data,
 headers : {'Accept' : 'application/json'}
};

$http.get(user.details_path, config).then(function(response) {
   // process response here..
 }, function(response) {
});

Answer 2

有兴趣在GET请求中发送params和header的人的解决方案

$http.get('https://www.your-website.com/api/users.json', {
        params:  {page: 1, limit: 100, sort: 'name', direction: 'desc'},
        headers: {'Authorization': 'Basic QWxhZGRpbjpvcGVuIHNlc2FtZQ=='}
    }
)
.then(function(response) {
    // Request completed successfully
}, function(x) {
    // Request error
});

完整的服务示例将如下所示

var mainApp = angular.module("mainApp", []);

mainApp.service('UserService', function($http, $q){

   this.getUsers = function(page = 1, limit = 100, sort = 'id', direction = 'desc') {

        var dfrd = $q.defer();
        $http.get('https://www.your-website.com/api/users.json', 
            {
                params:{page: page, limit: limit, sort: sort, direction: direction},
                headers: {Authorization: 'Basic QWxhZGRpbjpvcGVuIHNlc2FtZQ=='}
            }
        )
        .then(function(response) {
            if ( response.data.success == true ) { 

            } else {

            }
        }, function(x) {

            dfrd.reject(true);
        });
        return dfrd.promise;
   }

});

Answer 3

您甚至可以简单地将参数添加到网址的末尾：

$http.get('path/to/script.php?param=hello').success(function(data) {
    alert(data);
});

与script.php配对：

<? var_dump($_GET); ?>

导致以下javascript警报：

array(1) {  
    ["param"]=>  
    string(4) "hello"
}

Answer 4

以下是ASP.NET MVC中使用angular.js参数的HTTP GET请求的完整示例：

控制器：

public class AngularController : Controller
{
    public JsonResult GetFullName(string name, string surname)
    {
        System.Diagnostics.Debugger.Break();
        return Json(new { fullName = String.Format("{0} {1}",name,surname) }, JsonRequestBehavior.AllowGet);
    }
}

视图：

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.3.15/angular.min.js"></script>
<script type="text/javascript">
    var myApp = angular.module("app", []);

    myApp.controller('controller', function ($scope, $http) {

        $scope.GetFullName = function (employee) {

            //The url is as follows - ControllerName/ActionName?name=nameValue&surname=surnameValue

            $http.get("/Angular/GetFullName?name=" + $scope.name + "&surname=" + $scope.surname).
            success(function (data, status, headers, config) {
                alert('Your full name is - ' + data.fullName);
            }).
            error(function (data, status, headers, config) {
                alert("An error occurred during the AJAX request");
            });

        }
    });

</script>

<div ng-app="app" ng-controller="controller">

    <input type="text" ng-model="name" />
    <input type="text" ng-model="surname" />
    <input type="button" ng-click="GetFullName()" value="Get Full Name" />
</div>

Answer 5

对于使用参数i发送get请求

  $http.get('urlPartOne\\'+parameter+'\\urlPartTwo')

通过这个你可以使用自己的url字符串