我知道同样的问题已被问过几次,但我似乎无法绕过它。我已经完成了我找到的所有解决方案,但它不适用于我的情况。'日期'被记录为毛坯在Mysql数据库中而不是正确的date.Here是PHP代码
// initialize variables
$Vehicle_name = "";
$Vehicle_make = "";
$Vehicle_color="";
$Number_plate = "";
$Driver_name = "";
$Number_of_passengers = "";
$Date = "";
$Time = "";
$Security = "";
$id = 0;
$update = false;
if (isset($_POST['save'])) {
$Vehicle_name = $_POST['Vehicle_name'];
$Vehicle_make = $_POST['Vehicle_make'];
$Vehicle_color = $_POST['Vehicle_color'];
$Number_plate = $_POST['Number_plate'];
$Driver_name = $_POST['Driver_name'];
$Number_of_passengers = $_POST['Number_of_passengers'];
$Date = $_POST['Date '];
$Time = $_POST['Time'];
$Security = $_POST['Security'];
mysqli_query($db, "INSERT INTO vehicle (Vehicle_name,Vehicle_make,Vehicle_color,Number_plate,Driver_name,Number_of_passengers,Date,Time,Security ) VALUES ('$Vehicle_name','$Vehicle_make','$Vehicle_color','$Number_plate','$Driver_name','$Number_of_passengers','$Date','$Time','$Security ')");
$_SESSION['message'] = "Car registered";
header('location: welcome.php');
}`.
这也是日期文本框代码。
<div class="input-group">
<label>Date :</label>
<input type="date" name="Date" value="" required="yes" >
</div>
。
我花了很多时间试图解决这个问题,但都是徒劳的,请帮忙。请注意。
如果数据库字段的数据类型是date,那么您可以更改下面的代码行
$Date = date('Y-m-d', strtotime($_POST['Date']));
如果数据库字段的数据类型是datetime,那么您可以更改下面的代码行
$Date = date('Y-m-d H:i:s', strtotime($_POST['Date']));
在这里,我可以看到你在另一个领域分开时间,然后你可以改变下面的代码行
$Time = date('H:i:s', strtotime($_POST['Time']));