Python正则表达式从OCR结果中解析

Question

我试图解析以下文本

输入：

value1 @ M Temperature       1.30 ohmm       @ 74 00 degF  
value2 Q M. Temperature          1 70 ohmm @ 74.00 degF   
value3 @ m Temperature       110 ohmm        @ 74.00 degF  

预期产出：

value1 = 1.30  
value1 temp = 74.00 degF  

等等

我能够从文件中提取文本，但是有问题使OCR输出中的差异动态可解析。因此，当它显示为“临时”时，它仍会在其他事物中拉出预期值。

import re

with open('C:\Users\NthDS1\Documents\samp.txt', 'r') as f:
    data  = list()
    group = dict()
    for key, value in re.findall(r'(.*)Temperature\s*([\dE+-.]+)', f.read()):
        if key in group:
            data.append(group)
            group = dict()
        group[key] = value
    data.append(group)

print data

Answer 1

你可以试试这个：

import re
data = [dict(zip(['name', 'ohmm', 'degF'], re.findall('^[a-zA-Z0-9]+|[\d\.]+(?=\sohmm)|[\d\.]+(?=\sdegF$)', i.strip('\n'))) for i in open('filename.txt')]

输出：

[{'name': 'value1', 'ohmm': '1.30', 'degF': '00'}, {'name': 'value2', 'ohmm': '70', 'degF': '74.00'}, {'name': 'value3', 'ohmm': '110', 'degF': '74.00'}]

Answer 2

如果这是唯一的差异（点的空间），你可以试试

\b(?P<value>\d+(?:[. ]\d+)?)\b\s*
(?P<unit>\w+)

见a demo on regex101.com。

---

With the help of a little function, you could use

import re

data = """
value1 @ M Temperature       1.30 ohmm       @ 74 00 degF  
value2 Q M. Temperature          1 70 ohmm @ 74.00 degF   
value3 @ m Temperature       110 ohmm        @ 74.00 degF 
"""

rx = re.compile(r'''
    \b(?P<value>\d+(?:[. ]\d+)?)\b\s*
    (?P<unit>\w+)''', re.X)

def afterwork(match):
    value = match.replace(' ', '.')
    try:
        value = float(value)
    except ValueError:
        pass
    return value

values = [(afterwork(m.group('value')), m.group('unit')) 
          for m in rx.finditer(data)]
print(values)

生产

[(1.3, 'ohmm'), (74.0, 'degF'), (1.7, 'ohmm'), (74.0, 'degF'), (110.0, 'ohmm'), (74.0, 'degF')]