我如何将pyspark,石墨烯和烧瓶结合在一起?

问题描述 投票:0回答:1

在我的代码中,我正在使用pyspark进行数据操作,使用python graphene围绕我的数据构建graphql服务器,并使用flask服务graphql api。但是我面临一些我不知道为什么会发生的问题。

基本上,代码无法计算出正确的结果,而我假设总体上可能存在一些并发问题。

这里是我的代码的简化:

import graphene
from flask import Flask
from flask_graphql import GraphQLView

from pyspark.sql import SparkSession
from pyspark.conf import SparkConf

app = Flask(__name__)

spark = SparkSession.builder \
    .master("local") \
    .appName("Sencivil") \
    .config("spark.driver.allowMultipleContexts", "true") \
    .getOrCreate()

df = spark.read.format("csv")\
    .option("sep", ";")\
    .option("header", "true")\
    .load("./people.csv")\
    .cache()


class Birthdate(graphene.ObjectType):
    boys = graphene.Int()
    girls = graphene.Int()

    def __init__(self, bd):
        self.bd = bd

    def resolve_boys(self, info):
        boys = df.where(df.gender == 1).groupby("birthdate").count()
        return boys.count()

    def resolve_girls(self, info):
        girls = df.where(df.gender == 2).groupby("birthdate").count()
        return girls.count()


class Person(graphene.ObjectType):
    born = graphene.List(Birthdate)

    def resolve_born(self, info):
        bds = [Birthdate(row.asDict()["birthdate"])
               for row in df.select("birthdate").collect()]
        return bds


class Query(graphene.ObjectType):
    people = graphene.Field(Person)

    def resolve_people(self, info):
        return Person()


schema = graphene.Schema(query=Query)

app.add_url_rule(
    "/graphql", view_func=GraphQLView.as_view('graphql', schema=schema, graphiql=True))


if __name__ == "__main__":
    app.run(debug=True)

people.csv

birthdate;gender
13-01-1987;1
02-09-1986;2
13-01-1987;1
02-09-1986;2
12-04-1998;1

问题出在resolve_boys类的resolve_girlsBirthdate方法上,我希望从pyspark shell可以直接看到,男孩得到2个,女孩得到1个:

>>> boys = df.where(df.gender == 1).groupby("birthdate").count()
>>> boys.show()
+----------+-----+                                                              
| birthdate|count|
+----------+-----+
|13-01-1987|    2|
|12-04-1998|    1|
+----------+-----+

>>> girls = df.where(df.gender == 2).groupby("birthdate").count()
>>> girls.show()
+----------+-----+                                                              
| birthdate|count|
+----------+-----+
|02-09-1986|    2|
+----------+-----+

但是我只是从api中得到0:

GraphiQL

那么如何解决这个问题?

如果我更改了读取csv文件的代码,则改为像这样在本地创建数据框

# df = spark.read.format("csv")\
#     .option("sep", ";")\
#     .option("header", "true")\
#     .load("./people.csv")\
#     .cache()

df = spark.createDataFrame(
    [{'birthdate': "13-01-1987", "gender": 1},
     {'birthdate': "02-09-1986", "gender": 2}, 
     {'birthdate': "13-01-1987", "gender": 1},
     {'birthdate': "02-09-1986", "gender": 2}, 
     {'birthdate': "12-04-1998", "gender": 1}]
)

我得到正确答案:

enter image description here

因此,读取csv文件时会出现问题。但是为什么会这样呢?

python flask pyspark graphql graphene-python
1个回答
0
投票

您解决了您的问题吗?正如您所指出的,似乎数据帧未正确加载,但我相信它是由此行.load("./people.csv")\导致的,该行未指向您的csv文件。

以防万一,您能否将代码包装在try-except块中以打印出数据框或错误响应?

干杯!

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