Corona SDK的速度是否足以让像游戏这样的矮人堡垒？

Question

我想制作一个像游戏一样的矮人堡垒。 Corona SDK能够足够快吗？如何存储每个块的数据。由于我无法在Lua中创建枚举，我如何定义块的类型？

Answer 1

为什么你不能在Lua中制作一个枚举？只需使用一个简单的表。

brickType = { A = 1,
              B = 2,
              C = 3,
}

myFristBrick = { weight = 500,
                 volume = 50,
                 type = brickType.C
}

您可以使用Lua表对非常复杂的数据结构进行建模。因此，存储砖块数据是您应该关注的最少的问题。

Answer 2

我在元表中使用它来模拟enumTypes

local enumType_MT = {
    __newindex = function (t, k, v)
        if t [k] then
            print ('redeclaring enum type ' .. k .. ' not permited')
        else
            rawset (t, k, {})
            local c
            for c = 1, #v do
              rawset (t [k], v[c], c)
              rawset (t[k], c, v[c])
            end
         end
    end
}

local myEnumTypes = {}
setmetatable( myEnumTypes, enumType_MT )

myEnumTypes ['foo']  = {'brick_A', 'brick_B', 'brick_C'}
myEnumTypes ['doo']  = {'brick_E', 'brick_F', 'brick_G'}

myVar = myEnumTypes['foo'].brick_A
print (myVar) -- outputs 1
myVar = myEnumTypes['foo']['brick_C']
print (myVar) -- outputs 3
myVar = myEnumTypes['foo'][2]
print (myVar) -- outputs 'brick_B'

myVar = myEnumTypes['doo'].brick_A
print (myVar) -- outputs nil as brick_A not in doo
myVar = myEnumTypes['doo']['brick_C']
print (myVar) -- outputs nil as brick_C not in doo
myVar = myEnumTypes['doo'][2]
print (myVar) -- outputs 'brick_F'