我需要输入n行,每行包含1个“字符串”(char数组)。然后我想将它们存储在Word结构中并打印每个结构。我需要访问每个“字符串”的第一个和最后一个字符。
这些字符串在每个char之后总是有q个字母(除了最后一个)。示例:Hello - > Hqeqlqlqo
最重要的是,我还需要调用一个接收“字符串”的函数然后关闭'q'并将每个字符添加到这个新结构WordModified中,这样我就可以将它们全部打印出来了
所以,我的问题是:如何通过char访问两个结构字的单词?以及如何构建我的函数以排除'q'并连续追加WordModified结构中单词的字母。
#include <stdio.h>
#include <stdbool.h>
#include <string.h>
#define MAXCHAR 1100
typedef struct {
char name[1101];
} WordReceived;
typedef struct {
char name[1101];
} WordModified;
int main(void)
{
//char input[1101];
int nrlines, i;
scanf("Number of lines %d\n", &nrlines);
WordReceived words[nrlines];
WordModified wordsMod[nrlines];
for (i = 0; i < nrlines; ++i)
{
printf("String\n");
scanf("%s\n", words[i].name);
}
for (i = 0; i < nrlines; ++i)
{
printf("word %d: %s\n", i+1, words[i].name);
printf("First char: %s\n", words[i].name[0]);
printf("Last char: %s\n", words[i].name[n-1]);
}
for (i = 0; i < nrlines; ++i)
{
printf("word %d: %s\n", i+1, wordsMod[i].name);
}
return 0;
}
采用'q'字符的功能非常简单。请记住,我没有处理包含'q'字符的单词,你可以练习。
我修改了一下你的代码,你可以看到我的评论。
我不明白你为什么要访问每个单词的第一个和最后一个字符。
#include <stdio.h>
#include <stdbool.h>
#include <string.h>
#define MAXCHAR 1100 //What is for?
void CleanWord(char *word, char* mod_word);
typedef struct {
char name[1101];
} WordReceived;
typedef struct {
char name[1101];
} WordModified;
int main(void)
{
//char input[1101];
int nrlines, i;
printf("Number of lines: \n");
scanf(" %d", &nrlines);
WordReceived words[nrlines];
WordModified wordsMod[nrlines];
memset(words, 0, sizeof(words)); //Initialize the struct
memset(words, 0, sizeof(wordsMod)); //Initialize the struct
for (i = 0; i < nrlines; ++i)
{
printf("String\n");
scanf(" %s", words[i].name);
}
for (i = 0; i < nrlines; ++i)
{
CleanWord(words[i].name, wordsMod[i].name);
printf("word %d: %s\n", i+1, words[i].name);
printf("First char: %c\n", words[i].name[0]); //your code has %s formating but the variable is signle character
int n = strlen(words[i].name); //store the length of string
printf("Last char: %c\n", words[i].name[n-1]);
}
for (i = 0; i < nrlines; ++i)
{
printf("word %d: %s\n", i+1, wordsMod[i].name);
}
return 0;
}
/* This function remove the char 'q' from the 'word' and store the result to 'mod_word'*/
void CleanWord(char* word, char* mod_word)
{
int i,j = 0;
int word_size = strlen(word);
for(i = 0; i < word_size; i++)
{
if(word[i] != 'q')
mod_word[j++] = word[i];
}
}