使用CoreBluetooth检测Apple Watch

Question

我正在用iPhone的Core Bluetooth发现蓝牙设备，但它没有接收到Apple Watch。是不是我遗漏了什么？以下是我使用的代码。

#pragma mark - CBCentralManagerDelegate

// method called whenever you have successfully connected to the BLE peripheral
- (void)centralManager:(CBCentralManager *)central didConnectPeripheral:(CBPeripheral *)peripheral
{
}

// CBCentralManagerDelegate - This is called with the CBPeripheral class as its main input parameter. This contains most of the information there is to know about a BLE peripheral.
- (void)centralManager:(CBCentralManager *)central didDiscoverPeripheral:(CBPeripheral *)peripheral advertisementData:(NSDictionary *)advertisementData RSSI:(NSNumber *)RSSI
{     NSLog(@"%@", [peripheral name]);
}


// method called whenever the device state changes.
- (void)centralManagerDidUpdateState:(CBCentralManager *)central
{
switch ([central state])
{
    case CBCentralManagerStatePoweredOff:
        NSLog(@"CoreBluetooth BLE hardware is powered off");
        break;
    case CBCentralManagerStatePoweredOn:
        NSLog(@"CoreBluetooth BLE hardware is powered on and ready");
        [[self bluetoothManager] scanForPeripheralsWithServices:nil options:nil];
        break;
    case CBCentralManagerStateResetting:
        NSLog(@"CoreBluetooth BLE hardware is resetting");
        break;
    case CBCentralManagerStateUnauthorized:
        NSLog(@"CoreBluetooth BLE state is unauthorized");
        break;
    case CBCentralManagerStateUnknown:
        NSLog(@"CoreBluetooth BLE state is unknown");
        break;
    case CBCentralManagerStateUnsupported:
        NSLog(@"CoreBluetooth BLE hardware is unsupported on this platform");
        break;
    default:
        break;
}
}

Answer 1

当我运行以下代码时，我的Apple Watch出现了。

[self.centralManager retrieveConnectedPeripheralsWithServices:@[[CBUUID UUIDWithString:@"180A"]]];

180A 是设备信息服务

不知道你可以发现和订阅哪些特征，如果有的话，但你肯定可以检测到手表的存在。

Answer 2

U不使用核心蓝牙连接到苹果手表，你使用另一个框架称为连接性

https:/developer.apple.comdocumentationwatchconnectivityusing_watch_connectivity_to_communicate_between_your_apple_watch_app_and_iphone_app。