我正在尝试添加一个工厂模型的关系来做一些数据库种子,如下所示 - 注意我正在尝试为每个用户添加2个帖子
public function run()
{
factory(App\User::class, 50)->create()->each(function($u) {
$u->posts()->save(factory(App\Post::class, 2)->make());
});
}
但它抛出以下错误
Argument 1 passed to Illuminate\Database\Eloquent\Relations\HasOneOrMany::s
ave() must be an instance of Illuminate\Database\Eloquent\Model, instance
of Illuminate\Database\Eloquent\Collection given
我认为它与保存集合有关。如果通过分别调用帖子的每个工厂模型重新编写代码,它似乎工作。显然这不是很优雅,因为如果我想坚持10或发布给每个用户,那么我必须decalare 10或行,除非我使用某种for循环。
public function run()
{
factory(App\User::class, 50)->create()->each(function($u) {
$u->posts()->save(factory(App\Post::class)->make());
$u->posts()->save(factory(App\Post::class)->make());
});
}
* 更新 *
有没有什么方法可以将模型工厂嵌套到第3层?
public function run()
{
factory(App\User::class, 50)
->create()
->each(function($u) {
$u->posts()->saveMany(factory(App\Post::class, 2)
->make()
->each(function($p){
$p->comments()->save(factory(App\Comment::class)->make());
}));
});
}
试试这个。它对我有用:
factory(\App\Models\Auth\User::class, 300)->create()->each(function ($s) {
$s->spots()->saveMany(factory(\App\Models\Spots\Parking::class, 2)->create()->each(function ($u) {
$u->pricing()->save(factory(\App\Models\Payment\Pricing::class)->make());
}));
$s->info()->save(factory(\App\Models\User\Data::class)->make());
});
对于第三级嵌套关系,如果要使用正确的相应外键创建数据,可以循环创建帖子的所有结果,如下所示:
factory(App\User::class, 50)->create()->each(function($u) {
$u->posts()
->saveMany( factory(App\Post::class, 2)->make() )
->each(function($p){
$p->comments()->save(factory(App\Comment::class)->make());
});
});