这个问题已经在这里有一个答案:
我有一个包含日期范围一栏,我只是想拥有它提取到开始和结束日期分别。不知道这是直接可行与datetime.strptime
df_have = pd.DataFrame([[1, '01 Jan 2019-04 Jan 2019'], [2, '07 Jan 2019-11 Jan 2019']], columns=['Index', 'Range'])
Index Range
0 1 01 Jan 2019-04 Jan 2019
1 2 07 Jan 2019-11 Jan 2019
df_want = pd.DataFrame([[1, '01 Jan 2019', '04 Jan 2019'], [2, '07 Jan 2019', '11 Jan 2019']], columns=['Index', 'Start', 'End'])
Index Start End
0 1 01 Jan 2019 04 Jan 2019
1 2 07 Jan 2019 11 Jan 2019
谢谢
使用str.split
例如:
import pandas as pd
df_have = pd.DataFrame([[1, '01 Jan 2019-04 Jan 2019'], [2, '07 Jan 2019-11 Jan 2019']], columns=['Index', 'Range'])
df_have[["start", "end"]] = df_have.pop("Range").str.split("-", expand=True) #Thanks @ jezrael
print(df_have)
输出:
Index start end
0 1 01 Jan 2019 04 Jan 2019
1 2 07 Jan 2019 11 Jan 2019
import pandas as pd
df_have['Start']=df_have['Range'].map(lambda x:x.split('-')[0])
df_have['End']=df_have['Range'].map(lambda x:x.split('-')[1])
df_have.drop('Range', axis=1)
print(df_have)
Index Start End
0 1 01 Jan 2019 04 Jan 2019
1 2 07 Jan 2019 11 Jan 2019