我如何通过从变量$名1的值(比方说,它的bobsmith)取代janedoe
<?php
$name1 = $_GET["name"];
$curl = curl_init();
$user = "user1";
$password = "pass1";
curl_setopt_array($curl, array(
CURLOPT_URL =>'https://betawebservices.whatever.com/login/service/v4/SchemaData/INDIVIDUAL-
ACTIVITIES-University/USERNAME:janedoe/',
我希望我能说
<?php
$name1 = $_GET["name"];
$curl = curl_init();
$user = "user1";
$password = "pass1";
curl_setopt_array($curl, array(
CURLOPT_URL=>'https://betawebservices.whatever.com/login/service/v4/SchemaData/INDIVIDUAL- ACTIVITIES-University/USERNAME:$name1/',
......但是,这并不工作。谢谢
如果你把CURLOPT_URL的内容在双引号代替单引号应该能正常运行。
这将工作..
CURLOPT_URL=>'https://betawebservices.whatever.com/login/service/v4/SchemaData/INDIVIDUAL- ACTIVITIES-University/USERNAME:'.$name1.'/'