partition by day { function_call(day) } that doesn't work, but if I do ...

Question

please have a look at

user-defined functions usage restrictionspartition, specifically #1-2 (assuming I guessed correctly what your function,

range day from 1 to 50 step 1
| partition by day
{
   function_call(day)  
}

, does):

range day from 1 to 50 step 1
| partition by day
{
   function_call(10)  
}

Answer 1

User-defined functions that return a tabular expression can't be invoked with an argument that varies with the row context. function_call()A function taking at least one tabular input can't be invoked on a remote cluster.

A scalar function can't be invoked on a remote cluster.
1. toscalar()Depending on what your function,
does, you could achieve your goal in a different way. But you'll need to specify the logic of that function if you need further assistance.
如何在Kusto中使用
3. 通过调用一个以值为参数的函数来运行一个子查询？
那是行不通的，但如果我给一个常量的
4. 那么它将会工作，但它变成了一个具有相同参数的函数调用的联合，虽然不是我真正想要的......

function_call()如何使用partition通过调用以值为参数的函数运行子查询？ range day from 1 to 50 step 1