我想使用字符串类将字符串转换为二进制。一个字符一个字符地执行此操作的快速方法是什么?环形?或者有什么函数可以为我转换吗? 1 和 0 的二进制。
字符串是:
#include <string>
using namespace std;
int main(){
myString = "Hello World";
}
使用
std::bitset
会起作用:
#include <string>
#include <bitset>
#include <iostream>
using namespace std;
int main(){
string myString = "Hello World";
for (std::size_t i = 0; i < myString.size(); ++i)
{
cout << bitset<8>(myString.c_str()[i]) << endl;
}
}
输出:
01001000
01100101
01101100
01101100
01101111
00100000
01010111
01101111
01110010
01101100
01100100
尝试使用此 with 方法。示例:
#include <iostream>
#include <bitset>
using namespace std;
string TextToBinaryString(string words) {
string binaryString = "";
for (char& _char : words) {
binaryString +=bitset<8>(_char).to_string();
}
return binaryString;
}
int main()
{
string testText = "Hello World";
cout << "Test text: " << testText << "!\n";
cout << "Convert text to binary: " << TextToBinaryString(testText) << "!\n";
return 0;
}
结果代码:
Test text: Hello World!
Convert text to binary: 0100100001100101011011000110110001101111001000000101011101101111011100100110110001100100!
char * buf = data.c_str; //buf is binary
`QString StringToBinary::toBinary(QString s) { QString bin = "";
for (int i = 0; i < s.size(); ++i)
{
bin += QString::fromStdString(std::bitset<8>(s.at(i).unicode()).to_string());
}
q调试()<
return bin;
}`