我无法在Choropleth构造函数中获得key_on的正确值

问题描述 投票:0回答:1

我正在尝试为印度各州人口绘制一个choropleth地图。这是我的代码:

india_geo=r'e:/coursera/indiageo.geojson
world_map=folium.Map(location=[20.5937,78.9629],zoom_start=4)
folium.Choropleth(
    geo_data=india_geo.geojson,
    data=df_pop,
    key_on='features.properties.ID_1',
    columns=['Name', 'TOT_P'], 
    fill_color='YlOrRd', 
    fill_opacity=0.7, 
    line_opacity=0.2,
    legend_name='Distribution'
    ).add_to(world_map)
folium.LayerControl().add_to(world_map)
world_map

问题是,当我运行代码时,我的屏幕白屏了。我的数据框由州名及其人口组成:

  Name             TOT_P
0   JAMMU & KASHMIR    1493299
1   HIMACHAL PRADESH   392126
2   UTTARAKHAND        291903
3   RAJASTHAN          9238534
4   UTTAR PRADESH      1134273

到geojson文件的链接如下:

https://raw.githubusercontent.com/geohacker/india/master/district/india_district.geojson

python geojson choropleth
1个回答
0
投票

您需要在'id'上添加功能才能访问功能

with open(r'\india.GEOJSON') as f:
    geojson_counties = json.load(f)
for i in geojson_counties['features']:
    i['id'] = i['properties']['NAME_1']

并将key_on设置为

key_on='feature.id'
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