这是我在 Go 中的代码,我想一切都是正确的......
package main
import(
"fmt"
"encoding/json"
"net/http"
)
type Payload struct {
Stuff Data
}
type Data struct {
Fruit Fruits
Veggies Vegetables
}
type Fruits map[string]int
type Vegetables map[string]int
func serveRest(w http.ResponseWriter, r *httpRequest){
response , err := getJsonResponse()
if err != nil{
panic(err)
}
fmt.println(w, string(response))
}
func main(){
http.HandleFucn("/", serveRest)
http.ListenAndServe("localhost:1337",nil)
}
func getJsonResponse() ([]byte, error){
fruits := make(map[string]int)
fruits["Apples"] = 25
fruits["Oranges"] = 11
vegetables := make(map[string]int)
vegetables["Carrots"] = 21
vegetables["Peppers"] = 0
d := Data{fruits, vegetables}
p := Payload{d}
return json.MarshalIndent(p, "", " ")
}
这是我遇到的错误
API_Sushant.go:31: syntax error: unexpected string literal, expecting semicolon or newline or }
任何人都可以告诉我错误是什么吗....
您的示例中有一些小错别字。修复这些问题后,您的示例为我运行,没有出现
unexpected string literal
错误。另外,如果您想将 JSON 写入 http.ResponseWriter
,您应该将 fmt.Println
更改为 fmt.Fprintln
,如下面第 2 部分所示。
(1) 轻微错别字
// Error 1: undefined: httpRequest
func serveRest(w http.ResponseWriter, r *httpRequest){
// Fixed:
func serveRest(w http.ResponseWriter, r *http.Request){
// Error 2: cannot refer to unexported name fmt.println
fmt.println(w, string(response))
// Fixed to remove error. Use Fprintln to write to 'w' http.ResponseWriter
fmt.Println(w, string(response))
// Error 3: undefined: http.HandleFucn
http.HandleFucn("/", serveRest)
// Fixed
http.HandleFunc("/", serveRest)
(2) HTTP 响应中返回 JSON
因为
fmt.Println
写入标准输出,而 fmt.Fprintln
写入提供的 io.Writer,要在 HTTP 响应中返回 JSON,请使用以下命令:
fmt.Fprintln(w, string(response))