如何在C＃Mongodb强类型驱动程序中基于嵌套数组元素创建索引

Question

这个问题与this one的原理完全相同，但是当这个对象嵌套在集合的数组中时，我想在对象属性上使用强类型方法创建索引。

我可以用：

new CreateIndexModel<T>( Builders<T>.IndexKeys.Ascending( a ) )

其中a是访问直接属性的表达式。

但我发现没有类似的东西：

Builders<Library>.Filter.ElemMatch(x => x.Author.Books, b => b.IsVerified == false));

这样我就可以将一个对象的某个字段定义为索引，该对象嵌套在一个数组中，该数组是该集合的一个成员。

这有可能吗？怎么做？

Answer 1

考虑以下数据模型：

public class Course
{
   public string Name { get; set; }
   public string Teacher { get; set; }
}

public class Student
{
  public string Name { get; set; }
  public int Age { get; set; }
  public ReadOnlyCollection<Course> Courses { get; set; }
}

您可以按以下方式在字段课程上创建升序多键索引：

using MongoDB.Driver;
using System;
using System.Collections.Generic;
using System.Threading.Tasks;

namespace ConsoleApp1
{
  public static class Program
  {
    private static MongoClient Client;
    private static IMongoDatabase Database;
    private static IMongoCollection<Student> Collection;

    public static async Task Main(string[] args)
    {
      Client = new MongoClient();
      Database = Client.GetDatabase("test-index");
      Collection = Database.GetCollection<Student>("students");

      var courses1 = new List<Course>()
      {
        new Course { Name = "Math", Teacher = "Bob" }
      }.AsReadOnly();

      var courses2 = new List<Course>()
      {
        new Course { Name = "Computer Science", Teacher = "Alice" }
      }.AsReadOnly();

      var mark = new Student
      {
        Name = "Mark",
        Courses = courses1,
        Age = 20
      };

      var lucas = new Student
      {
        Name = "Lucas",
        Courses = courses2,
        Age = 22
      };

      await Collection.InsertManyAsync(new[] { mark, lucas }).ConfigureAwait(false);


      var model = new CreateIndexModel<Student>(
        Builders<Student>.IndexKeys.Ascending(s => s.Courses));

      await Collection.Indexes.CreateOneAsync(model).ConfigureAwait(false);

      Console.WriteLine("All done !");
    }
  }
}

此查询由您创建的索引提供：db.students.find({Courses: {"Name": "Math", "Teacher": "Bob"}})

如果您不想在整个数组课程上创建索引，而是希望在嵌套对象的字段Name（Course对象）上有索引，则可以采用以下方法：

using MongoDB.Driver;
using System;
using System.Collections.Generic;
using System.Threading.Tasks;

namespace ConsoleApp1
{
  public static class Program
  {
    private static MongoClient Client;
    private static IMongoDatabase Database;
    private static IMongoCollection<Student> Collection;

    public static async Task Main(string[] args)
    {
      Client = new MongoClient();
      Database = Client.GetDatabase("test-index");
      Collection = Database.GetCollection<Student>("students");

      var courses1 = new List<Course>()
      {
        new Course { Name = "Math", Teacher = "Bob" }
      }.AsReadOnly();

      var courses2 = new List<Course>()
      {
        new Course { Name = "Computer Science", Teacher = "Alice" }
      }.AsReadOnly();

      var mark = new Student
      {
        Name = "Mark",
        Courses = courses1,
        Age = 20
      };

      var lucas = new Student
      {
        Name = "Lucas",
        Courses = courses2,
        Age = 22
      };

      await Collection.InsertManyAsync(new[] { mark, lucas }).ConfigureAwait(false);


      var model = new CreateIndexModel<Student>(
        Builders<Student>.IndexKeys.Ascending("Courses.Name"));

      await Collection.Indexes.CreateOneAsync(model).ConfigureAwait(false);

      Console.WriteLine("All done !");
    }
  }
}

此查询由您创建的索引提供：db.students.explain("executionStats").find({"Courses.Name": "Math"})

在我的第二个例子中避免使用魔术字符串的一种可能方法是利用C＃运算符名称的强大功能：$"{nameof(Student.Courses)}.{nameof(Course.Name)}"

Answer 2

这是使用MongoDB.Entities便利库为嵌套字段创建索引的强类型方法。 [免责声明：我是作者]

using MongoDB.Entities;
using System.Collections.Generic;

namespace StackOverflow
{
    public class Program
    {
        public class Parent : Entity
        {
            public Child[] Children { get; set; }
        }

        public class Child
        {
            public List<Friend> Friends { get; set; }
        }

        public class Friend
        {
            public string Name { get; set; }
        }

        static void Main(string[] args)
        {
            new DB("test");

            DB.Index<Parent>()
              .Key(p => p.Children[-1].Friends[-1].Name, KeyType.Ascending)
              .Create();

        }
    }
}

以上命令在name字段上创建一个升序索引，该索引使用以下命令嵌套两层深度：

db.Parent.createIndex({
    "Children.Friends.Name": NumberInt("1")
}, {
    name: "Children.Friends.Name(Asc)",
    background: true
})