function sum() 2 fields with same id

Question

我正在尝试获取特定字段的总和。当我尝试将这些值放在一起时，我得到的 SUM 是错误的。 我有这个：

• reference: id_skill, user, level_paid

更具体的表格参考为：

id_skill	用户	level_paid
100	红色	1
100	红色	1
200	红色	2
200	红色	1

我想要的查询结果是，

id_skill	用户	level_paid
100	红色	2
200	红色	3

SELECT   
  SUM(level_paid) AS total,
FROM reference
WHERE user = 'Red'
GROUP BY 
  id_skill

我想要实现的是，如果“id_skill”的记录大于 1，则获取字段“level_paid”的总和。

Answer 1

您可以通过以下查询获得结果。

HAVING

子句将确保您仅根据

GROUP BY

条件对超过 1 条记录的值求和，例如至少有两个

id_skill

具有相同的值。

SELECT
  id_skill,   
  user,
  SUM(level_paid) AS level_paid
FROM reference
WHERE user = 'Red'
GROUP BY 
  id_skill, user
HAVING COUNT(*) > 1

Answer 2

我觉得

SELECT SUM(level_paid) AS total,

问题是如果你想打印 id_skill ，你也需要将查询更新为 users

SELECT SUM(level_paid) AS total, id_skill ,user FROM reference WHERE user = 'Red' GROUP BY id_skill

我还注意到您的查询中有一个额外的逗号，之前 from also remove that extra comma