我可以访问实现虚拟方法iObjectManager::getTile(const Course::ObjectId &id) = 0
的接口。我在继承的class ObjectManager:public Course::iObjectManager
中重新实现了上述方法,如下所示:
std::shared_ptr<Course::TileBase> getTile(const Course::ObjectId &id) override;
std::shared_ptr<Course::TileBase> ObjectManager::getTile(const Course::ObjectId &id)
{
qDebug() << "Looking for tile based on ID...\n";
for (unsigned i = 0; i < getMapSize(); i++) {
for (unsigned j = 0; j < getMapSize(); j++) {
std::shared_ptr<BoardPiece> tile = getGameMap().at(i).at(j);
if (tile->ID == id) {
qDebug() << "Tile found.\n";
return std::move(tile);
}
}
}
qDebug() << "No tile with given index...\n";
return nullptr;
}
问题出现了,当课程附带代码调用getTile
:什么也没发生。不会拨打qDebug
,并且不会打印任何内容。即使我已经正确实现了该功能,为什么仍无法调用该函数(或者缺少实现的那个)?
该函数的名称如下:
tile = lockObjectManager()->getTile(ID);
其中lockObjectManager
定义为
std::shared_ptr<iObjectManager> GameObject::lockObjectManager() const
{
std::shared_ptr<iObjectManager> handler = OBJECTMANAGER.lock();
Q_ASSERT(handler);
return handler;
}