无限模板递归,因为只有gcc才能优化bool表达式

问题描述 投票:1回答:1

我正在做一个词法施法者。请参阅下面的代码中简化的,有问题的部分。代码用clang和msvc编译,但无法用gcc编译。似乎,在lexicalCast的第一个参数中,std::enable_if gcc在评估之前尝试评估bool表达式的所有操作数,而clang和msvc进行优化并忽略LexicalCastable<>:: value表达式失败时对std::is_same的评估。我的问题是:

  • 做标准指定哪种行为是正确的?
  • 如何解决这个问题才能用GCC编译这段代码?

码:

#include <type_traits>
#include <string>

template<typename From, typename To>
class LexicalCastable;

template<typename To, typename From> typename
    std::enable_if<
           !std::is_same<std::string, To>::value
        && !std::is_same<std::string, From>::value
        && LexicalCastable<From, std::string>::value
        && LexicalCastable<std::string, To>::value,
To>::type lexicalCast(const From &from) {
    return lexicalCast<To>(lexicalCast<std::string>(from));
}

template<typename From, typename To>
class LexicalCastable
{
    template<typename TT>
    static auto test(int)
        -> decltype(lexicalCast<TT>(std::declval<From>()), std::true_type{});

    template<typename>
    static auto test(...)->std::false_type;

public:
    static const bool value = decltype(test<To>(0))::value;
};

static_assert(!LexicalCastable<std::string, std::string>::value, "");

gcc错误:

prog.cpp: In substitution of ‘template<class TT> static decltype ((lexicalCast<TT>(declval<From>()), std::true_type{})) LexicalCastable<From, To>::test(int) [with TT = std::__cxx11::basic_string<char>]’:
prog.cpp:35:45:   required from ‘const bool LexicalCastable<std::__cxx11::basic_string<char>, std::__cxx11::basic_string<char> >::value’
prog.cpp:19:3:   required by substitution of ‘template<class To, class From> typename std::enable_if<(((((! std::is_constructible<To, From>::value) && (! std::is_same<std::__cxx11::basic_string<char>, To>::value)) && (! std::is_same<std::__cxx11::basic_string<char>, From>::value)) && LexicalCastable<From, std::__cxx11::basic_string<char> >::value) && LexicalCastable<std::__cxx11::basic_string<char>, To>::value), To>::type lexicalCast(const From&) [with To = std::__cxx11::basic_string<char>; From = <missing>]’
prog.cpp:29:30:   required by substitution of ‘template<class TT> static decltype ((lexicalCast<TT>(declval<From>()), std::true_type{})) LexicalCastable<From, To>::test(int) [with TT = std::__cxx11::basic_string<char>]’
prog.cpp:35:45:   required from ‘const bool LexicalCastable<std::__cxx11::basic_string<char>, std::__cxx11::basic_string<char> >::value’
prog.cpp:19:3:   required by substitution of ‘template<class To, class From> typename std::enable_if<(((((! std::is_constructible<To, From>::value) && (! std::is_same<std::__cxx11::basic_string<char>, To>::value)) && (! std::is_same<std::__cxx11::basic_string<char>, From>::value)) && LexicalCastable<From, std::__cxx11::basic_string<char> >::value) && LexicalCastable<std::__cxx11::basic_string<char>, To>::value), To>::type lexicalCast(const From&) [with To = std::__cxx11::basic_string<char>; From = <missing>]’
prog.cpp:29:30:   [ skipping 889 instantiation contexts, use -ftemplate-backtrace-limit=0 to disable ]
prog.cpp:35:45:   required from ‘const bool LexicalCastable<std::__cxx11::basic_string<char>, std::__cxx11::basic_string<char> >::value’
prog.cpp:19:3:   required by substitution of ‘template<class To, class From> typename std::enable_if<(((((! std::is_constructible<To, From>::value) && (! std::is_same<std::__cxx11::basic_string<char>, To>::value)) && (! std::is_same<std::__cxx11::basic_string<char>, From>::value)) && LexicalCastable<From, std::__cxx11::basic_string<char> >::value) && LexicalCastable<std::__cxx11::basic_string<char>, To>::value), To>::type lexicalCast(const From&) [with To = std::__cxx11::basic_string<char>; From = <missing>]’
prog.cpp:29:30:   required by substitution of ‘template<class TT> static decltype ((lexicalCast<TT>(declval<From>()), std::true_type{})) LexicalCastable<From, To>::test(int) [with TT = std::__cxx11::basic_string<char>]’
prog.cpp:35:45:   required from ‘const bool LexicalCastable<std::__cxx11::basic_string<char>, std::__cxx11::basic_string<char> >::value’
prog.cpp:19:3:   required by substitution of ‘template<class To, class From> typename std::enable_if<(((((! std::is_constructible<To, From>::value) && (! std::is_same<std::__cxx11::basic_string<char>, To>::value)) && (! std::is_same<std::__cxx11::basic_string<char>, From>::value)) && LexicalCastable<From, std::__cxx11::basic_string<char> >::value) && LexicalCastable<std::__cxx11::basic_string<char>, To>::value), To>::type lexicalCast(const From&) [with To = std::__cxx11::basic_string<char>; From = <missing>]’
prog.cpp:40:43:   required from here
prog.cpp:29:49: fatal error: template instantiation depth exceeds maximum of 900 (use -ftemplate-depth= to increase the maximum)
   -> decltype(lexicalCast<TT>(std::declval<From>()), std::true_type{});
                               ~~~~~~~~~~~~~~~~~~^~
c++ templates gcc sfinae enable-if
1个回答
3
投票

如何解决这个问题才能用GCC编译这段代码

您可以使用保证短路的std::conjunction(C ++ 17)

template <typename To, typename From>
typename std::enable_if<
    std::conjunction<
           std::negation<std::is_same<std::string, To>>,
           std::negation<std::is_same<std::string, From>>,
           LexicalCastable<From, std::string>
           LexicalCastable<std::string, To>>::value,
    To>::type
lexicalCast(const From &from)
{
    return lexicalCast<To>(lexicalCast<std::string>(from));
}
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