取消数据透视表并在SQL中连接条件

Question

我有2张桌子：

资金

country   2002     2006    2010   2014
Chicago   1000    23000    4500   9076

勋章

year   sport   event    country   gender   medal_rank  medal
2006    A        Z      Chicago    F          2         silver
1924    B        ZZ     Newyork    M          3         bronze
2014    C        ZZZZ   Chicago    M          1         Gold
1967    B        ZZb    Newyork    M          3         bronze
2014    C        ZZa    Chicago    F          2         silver

我想取消像这样的基金中的数据

country    year    value
Chicago    2002    1000
Chicago    2006    23000
Chicago    2010    4500
Chicago    2014    9076

然后与Medals一起加入，仅将2002、2006、2010和2104年的奖牌栏计数，因为我们在Funds中仅具有那几年的价值。在最后一步中，我将价值/奖章数除以价值/奖章。

最终表应如下所示：

country    year    value     countofmedeals      value/medal
Chicago    2002    1000        0                     0
Chicago    2006    23000       1                     23000
Chicago    2010    4500        0                     0
Chicago    2014    9076        2                     4536

下面是我尝试的代码，但是它不起作用。

use RDG

select
    S.Yr,
    qu.year,
    s.Cost,
    count(qu.medal)
from
(
    select 
        country,
        yr, 
        Cost
    from Funds
    unpivot
    (
        Yr for Cost in ([2002],[2006],[2010],[2014])
    ) as u
) s
join medals qu
on (s.country=qu.country and s.Yr=qu.year)
group by s.Yr,qu.year,s.Cost

Answer 1

declare @Funds table
(
    country varchar(20),
    [2002] int,
    [2006] int,
    [2010] int,
    [2014] int
);
insert into @Funds(country, [2002], [2006], [2010], [2014])
values ('Chicago', 1000, 23000, 4500, 9076);


declare @Medals table
(
year int,
sport varchar(20),
event varchar(20),
country varchar(20),
gender char(1),
medal_rank tinyint,
medal varchar(20)
);
insert into @Medals(year, sport, event, country, gender, medal_rank, medal)
values
(2006, 'A', 'Z', 'Chicago', 'F', 2, 'silver'),
(1924, 'B', 'ZZ', 'Newyork', 'M', 3, 'bronze'),
(2014, 'C', 'ZZZZ', 'Chicago', 'M', 1, 'Gold'),
(1967, 'B', 'ZZb', 'Newyork', 'M', 3, 'bronze'),
(2014, 'C', 'ZZa', 'Chicago', 'F', 2, 'silver');

select
    S.country,
    S.Yr,
    qu.year /*??*/,
    s.value,
    count(qu.medal) as countofmedals,
    cast(isnull(s.value*1./nullif(count(qu.medal), 0), 0) as decimal(19,2)) as [value/medal]
from
(
    select 
        country,
        yr, 
        value
    from @Funds
    unpivot
    (
        value for yr in ([2002],[2006],[2010],[2014]) --!!!!
    ) as u
) s
left join @medals qu --!!!!
on (s.country=qu.country and s.Yr=qu.year)
group by s.country, s.Yr,qu.year/*??*/,s.value;