PHP提交选择

Question

我试图没有提交按钮，当用户选择值时表单是否有任何提交方式？

<form method="post" action="<?php echo $_SERVER['PHP_SELF']  ?>" >

    <table class="form">

            <select name="category" class="formfield" id="category">
                <option value="-1"> Category </option>
                <?php
                    $sql_contry = "SELECT * FROM category";
                    $rs_c = mysql_query($sql_contry);
                    while ($row_c = mysql_fetch_array($rs_c)) {
                        echo '<option value="'.$row_c['category'].'">'.$row_c['category'].'</option>';  
                    }
                ?>
             </select>

    </table>

</form>

Answer 1

这是一个例子

<form>
    <select name='myfield' onchange='this.form.submit()'>
      <option selected>Milk</option>
      <option>Coffee</option>
      <option>Tea</option>
    </select>
    <noscript><input type="submit" value="Submit"></noscript>
</form>

使用noscript标记，它允许不支持JavaScript的浏览器仍然可以运行。

Answer 2

是的 - 使用javascript：

HTML：

<form id="frm">
   <select onchange="onSelectChange();">
          <option>1</option>
           <option>1</option>
   <select>
</form>

JS：

function onSelectChange(){
 document.getElementById('frm').submit();
}

Answer 3

只需更改下面的代码，我没有检查代码，所以可能会有一些错误，如资本/小写字母，我不确定，它是submit（）或Submit（）等等..

<script language="javascript">
function submitForm(){
    var val = document.myform.category.value;
    if(val!=-1){
        document.myform.submit();
    }
}
</script>
<form method="post" name="myform" action="<?php echo $_SERVER['PHP_SELF']  ?>" >

    <table class="form">

            <select name="category" class="formfield" id="category" onchange="submitForm();">
                <option value="-1"> Category </option>
                <?php
                    $sql_contry = "SELECT * FROM category";
                    $rs_c = mysql_query($sql_contry);
                    while ($row_c = mysql_fetch_array($rs_c)) {
                        echo '<option value="'.$row_c['category'].'">'.$row_c['category'].'</option>';  
                    }
                ?>
             </select>

    </table>

</form>

Answer 4

<form action="product.php" method="POST">
<select onchange="this.form.submit();" name="prod">
    <option value="">Select product</option>
    <option value="1">abc</option>
    <option value="2">def</option>
    <option value="3">ghi</option>
    <option value="4">jkl</option>
    <option value="5">mno</option>
</select>