从ID A中选择最新数据

问题描述 投票:0回答:1

我有这样的数据:

ID  TRANS_ID  CREATED_DATE             STATUS
----------------------------------------------
1   AA        2017-05-19 02:00:00      WAITING
2   AA        2017-05-20 02:00:00      IN_PROCESS
3   BB        2017-05-19 02:00:00      WAITING
4   CC        2017-05-19 02:00:00      WAITING
5   CC        2017-05-20 02:00:00      IN_PROCESS

我想像这样在表格视图中显示数据:

ID  TRANS_ID  CREATED_DATE             STATUS
----------------------------------------------
2   AA        2017-05-20 02:00:00      IN_PROCESS
3   BB        2017-05-19 02:00:00      WAITING
5   CC        2017-05-20 02:00:00      IN_PROCESS

我从每个trans_id中获取最新数据,但运行了此查询,但它不起作用

select id, max(created_date), trans_id, status
from table_a
group by a.transaction_id
oracle oracle11g oracle12c
1个回答
0
投票

一个选项是使用相关子查询进行过滤:

select t.*
from mytable t
where t.created_date = (
    select max(t1.created_date) from mytable t1 where t1.trans_id = t.trans_id
)

或者,您可以使用窗口功能:

select id, trans_id, created_date, status
from (
    select t.*, rank() over(partition by trans_id order by created_date desc) rn
    from mytable t
) t
where rn = 1

如果有的话,可以使用领带。如果您不想要领带,则可以使用row_number()代替rank()

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