如何返回Wiremock集成测试的故障代码？

Question

我编写了许多成功的测试来证明HttpStatus代码已正确返回，但是我现在正在寻找验证返回的Fault代码如下。通常我会说

 assertThat(actualResponse.getStatusCode(), is(status));

获取Http状态代码。如何验证故障代码？我目前有以下内容，但不确定如何从ActualResponse正文返回错误代码。

public void shouldReturnSuitableStatusCodeForScenario(String requestFileName,Fault fault, String actualResponseFileName) throws JSONException {
    //Given
    String createRequest = readJsonFromFile(DIRECTORY, requestFileName);

    //When
    ResponseEntity<String> actualResponse = stub.postForEntity(HTTP_LOCALHOST_8081 + "/v1/transaction/", createRequest, String.class);

    //Then
    assertThat(actualResponse, is(fault));
    JSONAssert.assertEquals(readJsonFromFile(DIRECTORY, actualResponseFileName), actualResponse.getBody(), true);
}

当前存根，省略了一些brevit代码：

.willReturn(aResponse() .withHeader(CONTENT_TYPE, APPLICATION_JSON_VALUE) .withFault(Fault.MALFORMED_RESPONSE_CHUNK) .withBodyFile("/malformed_chunk_response.json")));

Answer 1

例如，模拟500，这应该起作用：

 stubFor(post(urlPathEqualTo("/v1/transaction/"))
                .withRequestBody(equalToJson(createRequest))
                .willReturn(aResponse()
                        .withStatus(500)
                        .withBody(responseBody)))

要使用所有这些方法（例如stubFor，post）：

import static com.github.tomakehurst.wiremock.client.WireMock.*