如何简化?在此先感谢:)
a_list = []
for a, blah in enumerate(bunch_of_As.blahs):
if a.name == "WHATEVER":
for msg in a:
if msg.type == "value 1":
a_list.append(a)
elif msg.type == "value 2":
if msg.time != 0:
do_something(a)
a_list.remove(a)
可以简化此过程,因为您多次不必要地在a_list上添加和删除a元素
for a in bunch_of_As:
if a.name == "WHATEVER":
counter1 = 0
counter2 = 0
for msg in a:
if msg.type == "value 1":
counter1 += 1
elif msg.type == "value 2":
counter1 += -1
if msg.time != 0:
counter2 += 1
for n in range(counter1):
a_list.append(a)
for n in range(counter2):
do_something(a)
只有我有两个问题或假设,我认为“值1”的数量=>(大于或等于)num“值2”并且对a的do_something(a)效果为null
显然,这是更多的代码行,但是减少了附加删除的不必要过程