打开覆盖层时，我有一个页面正在加载并要求进行引脚验证。 pin 检查是通过 php on action="" 这一切正常，但我不知道如何在引脚正确后自动关闭覆盖层。我没有任何问题显示要单击的关闭按钮，但我希望它自动...
脚本是：
<script>
function on() {document.getElementById("overlay").style.display = "block";}
function off() {document.getElementById("overlay").style.display = "none";}
</script>
我可以用这个在 php 中关闭它，但是我怎样才能自动完成它？
<body class="page" onLoad="on();" >
<!--##################################### -->
<!--##### OVERLAY ####################### -->
<!--##################################### -->
<div id="overlay" >
<div id="suche">
<form class="was-validated" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>" autocomplete="off" id="buchen2">
<div class="form-row">
<div class="form-group col-md-4" >
<label for="usr">Enter Security PIN<div class="toolitip"> <a class="fa fa-info-circle" style="color: blue;"></a><span class="toolitiptext">Please enter your security PIN. If you do not have a PIN, ask the administrator! </span></div></label>
<input type="password" class="form-control" id="pin" name="pin" pattern="[0-9]{4}" onChange="submit();" required>
</div>
</div>
</form>
<?
include('db.php');
?>
<?
$pin = $_POST["pin"];
$ergebnis = $dbconnection->query("select usr, pin from user where usr = '$user' limit 1")
or die($dbconnection->error);
while($row = $ergebnis->fetch_object()){
$pinD=$row->pin;
}
if ($pin == $pinD) {
echo "<script>
function off() {
document.getElementById('overlay').style.display = 'none';
}
</script>";
echo "<p> Code is good! Please close the Overlay to continue </p>";
echo "<button type='button' onclick='off()' class='btn btn-primary btn-lg' name='erledigt'>CLOSE and continue</button> ";
echo "<script>
off();
</script>";
echo "<script>
function off() {
document.getElementById('overlay').style.display = 'none';
}
</script>";
}
else {
echo "<p> You must enter the correct code</p>";
}
?>
</div>
</div>
<!--##################################### -->
<!--##### OVERLAY ####################### -->
<!--##################################### -->
在 php if 语法中自动卸载覆盖层。 我只能使用 onclick="off" 但如何在不点击的情况下运行“off”？
我不明白你需要 javascript 做什么。只需首先执行 PHP 逻辑，然后输出覆盖（如果未输入 PIN 或输入错误的 PIN）或不输出（如果 PIN 正常）。
选项1：无JS
<?php
$pin_ok = false;
$pin_checked = false;
if(isset($_POST['pin'])) {
// Is form submit
$pin_checked = true;
if($_POST['pin'] == '12345') {
// PIN ok
$pin_ok = true;
}
}
?>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Document</title>
</head>
<body class="page" onLoad="on();" >
<?php if(!$pin_ok) { ?>
<!--##################################### -->
<!--##### OVERLAY ####################### -->
<!--##################################### -->
<div id="overlay" >
<div id="suche">
<form class="was-validated" method="post" action="" autocomplete="off" id="buchen2">
<div class="form-row">
<div class="form-group col-md-4" >
<label for="usr">Enter Security PIN<div class="toolitip"> <a class="fa fa-info-circle" style="color: blue;"></a><span class="toolitiptext">Please enter your security PIN. If you do not have a PIN, ask the administrator! </span></div></label>
<input type="password" class="form-control" id="pin" name="pin" pattern="[0-9]{4}" onChange="submit();" required>
</div>
</div>
</form>
<?php
if($pin_checked) {
// This happens only if wrong PIN was submitted
echo "<p>You must enter the correct code</p>";
}
?>
</div>
</div>
<!--##################################### -->
<!--##### OVERLAY ####################### -->
<!--##################################### -->
<?php } //if(!$pin_ok) ?>
[...] REST OF YOUR CONTENT HERE [...]
</body>
</html>
如果您有其他使用 javascript 的原因，请公开它，我很乐意用更多选项来扩展此答案。