在React js中点击回车键时触发onblur事件

Answer 1

代替

onKeyPress

，使用

onKeyDown

来检测

keyCode

事件。

<input type="text"
    style={{marginTop:'20%', marginLeft:'40%'}} 
    value={value} 
    onFocus={onFocus} 
    onChange={e => setValue(e.target.value)}
    onKeyDown={(e) => this.handleKeyPress(event)}
/>

函数会是这样的，

handleKeyPress(e){
   if(e.keyCode === 13){
     e.target.blur(); 
     //Write you validation logic here
   }
}

Answer 2

使用

refs

和

this.inputRef.current.blur()

。这是可行的解决方案。

class App extends React.Component {
  constructor(props) {
    super(props);
    this.inputRef = React.createRef();
    this.state = {
      value: ""
    };
  }
  keypressHandler = event => {
    if (event.key === "Enter") {
      this.setState({ value: this.inputRef.current.value });
      this.inputRef.current.blur();
      this.inputRef.current.value = "";
    }
  };
  render() {
    return (
      <div>
      <label>Enter Text</label>
        <input
          type="text"
          ref={this.inputRef}
          onKeyPress={event => this.keypressHandler(event)}
        />
        <p>{this.state.value}</p>
      </div>
    );
  }
}
ReactDOM.render(<App/>, document.getElementById('root'));

<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.6.3/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.6.3/umd/react-dom.production.min.js"></script>
<div id='root' />

Answer 3

一行是：

<input
...
onKeyDown={(e) => (e.key === "Escape") && e.target.blur()}    
/>