我正在尝试制作一个程序,其中用户输入两个素数,然后将它们相乘,并且完成了(a-1)*(b-1)的另一种计算(a和b是输入的素数) 。我创建了一个函数来检查输入的数字,如果数字不是素数,将要求用户重新输入数字。但是,当我对此进行测试时,我注意到,如果用户输入了一个IS N'T素数,然后重新输入一个素数,则计算将基于IS N'T素数。例如。如果用户输入2和4,由于4不是质数,他们会被要求输入另一个数字,例如3,计算将基于数字2和4。
我该如何纠正它,以便使用有效的质数而不是最初输入的无效数?
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using static System.Math;
using System.Numerics;
namespace example
{
class Program
{
class Co_Prime
{
static int gcd(int c, int calculation) //greatest common divider
{
if (c == 0 || calculation == 0)
return 0;
if (c == calculation)
return c;
if (c > calculation)
return gcd(c - calculation, calculation);
return gcd(c, calculation - c);
}
// check if coprime
static void coprime(ref int c, int calculation)
{
if (gcd(c, calculation) == 1)
Console.WriteLine("Yes that is Co-Prime");
else
do
{
Console.WriteLine("No that isn't Co-Prime");
Console.WriteLine("Please enter a number which is Co-Prime");
c = int.Parse(Console.ReadLine());
coprime(ref c, calculation);
} while (gcd(c, calculation) != 1);
}
static int Prime_a(int a) //check a is prime
{
if (a <= 1) return 0;
for (int i = 2; i <= a / 2; i++)
{
if (a % i == 0)
{
return 0; //not prime
}
}
return 1;
}
static void result(int a) //outputs if a is prime/or not
{
if (Prime_a(a) != 0)
{
Console.WriteLine(a + " is a prime number");
}
else do
{
Console.WriteLine(a + " isn't prime number");
Console.WriteLine();
Console.WriteLine("Please make sure you enter a prime number");
a = int.Parse(Console.ReadLine());
} while (Prime_a(a) == 0);
}
static int Prime_b(int b) //checks b is prime
{
if (b <= 1) return 0;
for (int i = 2; i <= b / 2; i++)
{
if (b % i == 0)
{
return 0; //isn't prime
}
}
return 1;
}
static void resultb(int b) //states if b is prime/or not
{
int result = Prime_b(b);
if (Prime_b(b) != 0)
{
Console.WriteLine(b + " is a prime number");
}
else do
{
Console.WriteLine(b + " is not a prime number");
Console.WriteLine("Please make sure you enter a prime number");
b = int.Parse(Console.ReadLine());
} while (Prime_b(b) == 0);
}
static void Main(string[] args)
{
int a;
Console.WriteLine("Enter a prime number for a");
a = int.Parse(Console.ReadLine());
Console.WriteLine();
result(a);
Console.WriteLine();
int b;
Console.WriteLine("Enter a prime number for b");
b = int.Parse(Console.ReadLine());
Console.WriteLine();
resultb(b);
Console.WriteLine();
int total = a * b;
Console.WriteLine("The total of the prime numbers is = " + total);
BigInteger calculation = (a - 1) * (b - 1); //calculation
Console.WriteLine();
Console.WriteLine("The result of (a-1) * (b-1) = " + calculation);
Console.WriteLine();
}
}
}
}
我正在尝试制作一个程序,其中用户输入两个素数,然后将它们相乘,并且完成了(a-1)*(b-1)的另一种计算(a和b是输入的素数) 。 ...
您应该扩展result
和resultb
函数,以便它返回新的提示有效数字
int b;
Console.WriteLine("Enter a prime number for b");
b = int.Parse(Console.ReadLine());
Console.WriteLine();
resultb(b);
Console.WriteLine();