我有这样的列表
[255, 0, 0, 255, 0, 0, 255, 0, 0, 255, 0, 0, 127, 0, 255, 127, 0, 255, 127, 0, 255, 127, 0, 255, 127, 0, 255, 0, 127, 255, 0, 127, 255, 0, 127, 255, 0, 127, 255, 0, 127, 255, 0, 127, 255, 0, 127, 255]
什么是转换成3对（rgb）的最佳方法，里面是元组
pixel = [(255,0,0),(255,0,0),(255,0,0),(255,0,0),(127,0,255),(127,0,255),(127,0,255),(127,0,255),(127,0,255),(0,127,255),(0,127,255),(0,127,255),(0,127,255),(0,127,255),(0,127,255),(0,127,255)]
尝试使用列表理解：
print([l[i:i + 3] for i in range(0, len(l), 3)])