我有这个查询,但我似乎找不到如何将WhereRestrictionOn 设置为OR。现在它们的功能为 AND,但我想要一个或另一个。
var privateInfo = Session.QueryOver<ConContact>()
.JoinAlias(c => c.PrivateInfos, () => pi)
.WhereRestrictionOn(c => c.FirstName).IsLike(_selectedFirstLetter + "%")
.WhereRestrictionOn(c => c.LastName).IsLike(_selectedFirstLetter + "%") // todo: change to firstname OR lastname
.Where(c => c.Status == ContactStatus.Approved)
.Select(
Projections.Property("pi.Id").WithAlias(() => sri.Id),
Projections.Property("FirstName").WithAlias(() => sri.Name), //todo: get fullname here => Add concontact object in privateinfo
Projections.Property("pi.Address").WithAlias(() => sri.Address),
Projections.Constant("Contact").WithAlias(() => sri.Type)
)
.TransformUsing(Transformers.AliasToBean<SearchResultInfo>())
.List<SearchResultInfo>()
.ToList();
非常感谢您的帮助!
解决方案:
var privateInfo = Session.QueryOver<ConContact>()
.JoinAlias(c => c.PrivateInfos, () => pi)
.Where(
Restrictions.Disjunction()
.Add(Restrictions.Like("FirstName", _selectedFirstLetter + "%"))
.Add(Restrictions.Like("LastName", _selectedFirstLetter + "%"))
)
.Where(c => c.Status == ContactStatus.Approved)
.Select(
Projections.Property("pi.Id").WithAlias(() => sri.Id),
Projections.Property("FirstName").WithAlias(() => sri.Name), //todo: get fullname here => Add concontact object in privateinfo
Projections.Property("pi.Address").WithAlias(() => sri.Address),
Projections.Constant(NewObjectType.Contact).WithAlias(() => sri.Type)
)
.TransformUsing(Transformers.AliasToBean<SearchResultInfo>())
.List<SearchResultInfo>()
.ToList();
顶级
.Where()
族(包括WhereRestrictionOn
)总是用AND连接。所以我们必须明确使用类似的东西:
Restrictions.Or(restriction1, restriction1)
Restrictions.Disjunction().Add(restriction1).Add(restriction2).Add(...
所以,这可能就是我们的情况:
.Where(
Restrictions.Disjunction()
.Add(Restrictions.On<ConContact>(c => c.FirstName)
.IsLike(_selectedFirstLetter, MatchMode.Start))
.Add(Restrictions.On<ConContact>(c => c.LastName)
.IsLike(_selectedFirstLetter, MatchMode.Start))
// more OR ...
//.Add(Restrictions.On<ConContact>(c => c.MiddleName)
// .IsLike(_selectedFirstLetter, MatchMode.Start))
)
如此处讨论:16.2。简单的表达式,对于简单的东西我们甚至可以
use ||
(引用小例子):
.Where(p => p.Name == "test name" && (p.Age > 21 || p.HasCar))
.Where(x=> x.Name.Islike("term", MatchMode.AnyWhere) || x.Age.isLike("termAge", MatchMode.AnyWhere))
enter code here